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Anna [14]
3 years ago
8

Please help due today

Mathematics
2 answers:
Feliz [49]3 years ago
6 0

Answer:

55

Step-by-step explanation:

all of the angles in a triangle ALWAYS add up to 180 degrees.

do the math.

Ganezh [65]3 years ago
5 0
X=55.
The sum of a triangle is always 180. You find the given angles and subtract them from 180 to find your third angle! hope this helps
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What are the roots of the polynomial equation x^3-6x=3x^2-8? Use a graphing calculator and a system of equations.
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Solve the triangle given that a=19 b=16, c=11.
kirill [66]

Answer:

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

Step-by-step explanation:

From statement we know all sides of the triangle (a, b, c), but all angles are unknown (A, B, C). (Please notice that angles with upper case letters represent the angle opposite to the side with the same letter but in lower case) From Geometry it is given that sum of internal angles of triangles equal 180º, we can obtain the missing information by using Law of Cosine twice and this property mentioned above.

If we know that a = 19, b = 16 and c = 11, then the missing angles are, respectively:

Angle A

a^{2} = b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A (1)

A = \cos^{-1}\left(\frac{b^{2}+c^{2}-a^{2}}{2\cdot b\cdot c} \right)

A = \cos^{-1}\left[\frac{16^{2}+11^{2}-19^{2}}{2\cdot (16)\cdot (11)} \right]

A \approx 87.395^{\circ}

Angle B

b^{2} = a^{2}+c^{2}-2\cdot a\cdot c \cdot \cos B (2)

B = \cos^{-1}\left(\frac{a^{2}+c^{2}-b^{2}}{2\cdot a\cdot c} \right)

B = \cos^{-1}\left[\frac{19^{2}+11^{2}-16^{2}}{2\cdot (19)\cdot (11)} \right]

B\approx 57.271^{\circ}

Angle C

C = 180^{\circ}-A-B

C = 180^{\circ}-87.395^{\circ}-57.271^{\circ}

C = 35.334^{\circ}

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

8 0
3 years ago
I will give brainliest!!!
Licemer1 [7]

The equation would be worded as: 2m+16=36.

Solve! Using the subtraction property of equality, 2m=20. Then the division property of equality lets us figure out that m=10.

Hope that helped! Happy SOLVING!


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