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3 years ago

9

Find the only positive integer number less than 20,000 that is also the sum of three positive integers, all containing exactly 7

factors.

1 answer:

NeX [460]3 years ago

5 0

Answer:

sim eu também preciso desta

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What is the simplified form of 2/x^2-x - 1/x?

Pachacha [2.7K]

Answer: $\bold{(C)\ \dfrac{3 - x}{x(x-1)}}$

<u>Step-by-step explanation:</u>

$\dfrac{2}{x^2-x}-\dfrac{1}{x}$

$=\dfrac{2}{x(x-1)}+\dfrac{-1}{x}$

$=\dfrac{2}{x(x-1)}+\dfrac{-1}{x}\bigg(\dfrac{x-1}{x-1}\bigg)$

$=\dfrac{2}{x(x-1)}+\dfrac{-x+1}{x(x-1)}$

$=\dfrac{2-x+1}{x(x-1)}$

$=\dfrac{3-x}{x(x-1)}$

8 0

4 years ago

In a two-player game, five cards, numbered 1 through 5, are placed in a bag. A card is drawn at random, and the players look at

IceJOKER [234]

Answer:

If it is less than 3, Player 1 earns 3 points.

If not, Player 2 earns 2 points.

Step-by-step explanation:

<u>Player 1</u> :

p(N < 3) = p(N = 1 or N = 2) = 2/5

<u>Player 2</u> :

p(N ≥ 3) = p(N = 3 or N = 4 or N = 5) = 3/5

<u>We notice that</u> :

p(N < 3) × 3 = (2/5) × 3 = 6/5

On the other hand,

p(N ≥ 3) × 2 = (3/5) × 2 = 6/5

since ,the probability player 1 win multiplied by the associated number of points (3)

is equal to

the probability player 2 win multiplied by the associated number of points (2).

Then the game is fair.

8 0

2 years ago

Read 2 more answers

Given the function f(x) = 3x + 1, what is the value of f(9)

Aliun [14]

f(x) = 3x + 1

f(9) = 3(9) + 1

f(9) = 27 + 1

f(9) = 28

f(9) = 28. I hope this helps! I have a g00gle classroom where I help with algebra including this. If you are interested, please consider joining. I will post the class code in the comments if it would let me. Sorry it wouln't let me type g0ogle properly.

4 0

3 years ago

Read 2 more answers

A certain forest covers an area of

iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

if

4500 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\$

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\$

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\$

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year 4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\$

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year 5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\$

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year 6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\$

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0

3 years ago

How many non-congruent triangles can be formed by connecting 3 of the vertices of the cube?

alexira [117]

Answer:

The number of non-congruent triangles that can be formed by connecting 3 of the vertices of the cube is 3 non-congruent triangles

Step-by-step explanation:

From the three dimensional shape of a cube, triangles can be constructed from;

1) 6 side faces

2) 4 front face to opposite vertices triangles

3) 4 rear face to opposite vertices triangles

Each face can produce ₄C₃ = 4 triangles

Therefore;

The total number of triangles that can be formed = 4 × 6 + 4 × 4 + 4 × 4 = 56 triangles

Of the 56 triangles, it will be found that all 24 triangles from the different 6 direct faces will have the same dimension of 1, 1, √2 are congruent

The 24 triangles formed by the sides of the faces and an adjacent diagonal have the same dimension of 1, √2, √3 and are congruent

The 8 triangles formed by joining the three diagonals have the same dimension of √2, √2, √2 are congruent

Therefore, the 56 triangles comprises of a combination of three non-congruent triangle.

There are only 3 observed non congruent triangles formed by connecting three of the vertices of the cube.

3 0

3 years ago

Read 2 more answers