Question
Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee for installation. Which inequality can be used to find out when the monthly cost for Cable company A is less than Cable company B?
a)39x+30<45x+18
b) 45x+18>39x+30
c) 45x+18<39x+30
d)39x+18<45x+30
Answer:
c) 45x+18<39x+30
Step-by-step explanation:
Step 1
We have to find the Algebraic expressions for the cable companies
Cable company A charges $45 a month for cable plus a $18 installation fee.
Let the number of months be represented as x
Hence, this is represented as:
$45 × x + $18
= 45x + 18
Cable B charges $39 a month for cable plus a $30 fee for installation.
Let the number of months be represented as x
Hence, this is represented as:
$39 × x + $30
= 39x + 30
The inequality that can be used to find out when the monthly cost for Cable company A is less than Cable company B?
= Cable company A < Cable company B
= 45x + 18 < 39x + 30
Therefore option c is correct
Answer:
You didn't tell us much on what to do, so I just guessed you wanted it simplified. If you want a different answer, please do so tell me and I'll edit my answer to fit.
Simplified: 10
+ 
- 9
So 12 out of 32=12/32=6/16=3/8
percent means parts out of 100 so
x/100=x%
3/8=0.375/1
0.375/1 times 100/100=37.5/100=37.5%
answer is 37.5%
Answer 6
Step-by-step explanation:
remove the para-these 2 x 3 x 5 / 2 power of 2 + 1
you get 30/ 5
30/5 =
6 therefore your answer is 6
Answer:
1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253421170679
