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ICE Princess25 [194]

3 years ago

13

The volume of sphere Q is 50% more than the volume of sphere P. The volume of sphere R is 50% more than the volume of sphere Q.

Find the volume of sphere P as a fraction of sphere R. Write your answer in the form a/b

1 answer:

STALIN [3.7K]3 years ago

6 0

<h2>Use this link to find your answer</h2><h2>http://ldh.la.gov/</h2>

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A fair coin is tossed repeatedly with results Y0, Y1, Y2, . . . that are 0 or 1 with probability 1/2 each. For n ≥ 1 let Xn = Yn

Gekata [30.6K]

Answer:

False. See te explanation an counter example below.

Step-by-step explanation:

For this case we need to find:

$P(X_{n+1} = | X_n =i, X_{n-1}=i') =P(X_{n+1}=j |X_n =i)$ for all $i,i',j$ and for $X_n$ in the Markov Chain assumed. If we proof this then we have a Markov Chain

For example if we assume that $j=2, i=1, i'=0$ then we have this:

$P(X_{n+1} = | X_n =i, X_{n-1}=i') =\frac{1}{2}$

Because we can only have $j=2, i=1, i'=0$ if we have this:

$Y_{n+1}=1 , Y_n= 1, Y_{n-1}=0, Y_{n-2}=0$ , from definition given $X_n = Y_n + Y_{n-1}$

With $i=1, i'=0$ we have that $Y_n =1 , Y_{n-1}=0, Y_{n-2}=0$

So based on these conditions $Y_{n+1}$ would be 1 with probability 1/2 from the definition.

If we find a counter example when the probability is not satisfied we can proof that we don't have a Markov Chain.

Let's assume that $j=2, i=1, i'=2$ for this case in order to satisfy the definition then $Y_n =0, Y_{n-1}=1, Y_{n-2}=1$

But on this case that means $X_{n+1}\neq 2$ and on this case the probability $P(X_{n+1}=j| X_n =i, X_{n-1}=i')= 0$ , so we have a counter example and we have that:

$P(X_{n+1} =j| X_n =i, X_{n-1}=i') \neq P(X_{n+1} =j | X_n =i)$ for all $i,i', j$ so then we can conclude that we don't have a Markov chain for this case.

6 0

3 years ago

If f(x)=3x+2, what is f(5)

patriot [66]

Answer:

<h2>f(5) = 17</h2>

Step-by-step explanation:

f(x)=3x+2

To find f (5) replace every x in f(x) by 5

That's

f(5) = 3(5) + 2

= 15 + 2

<h3>= 17</h3>

Hope this helps you

5 0

3 years ago

What is the height of a cubic prism containing 125 cubes

ladessa [460]

<h3>s³=l,b,h</h3><h3>so,</h3><h3>s³=125</h3>

$s = \sqrt[3]{125}$

<h3>s=5 and height =5 cubes</h3><h3>hope it helps :-)</h3>

6 0

3 years ago

Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After runni

vodomira [7]

First, we need her speed as it will serve as the slope of the equation.
Distance = 2 km
time = 18 min
Speed = 1/9 km/min
k = (1/9)t
Where k is the distance in km and t is the time in minutes.

6 0

3 years ago

The rectangle is 16 inches by 25 inches. If the scale is 4 in :5 ft what is the length and width of the rectangle in feet.

Alenkasestr [34]

Answer:

The length and width of the rectangle are 20 feet and 31.25 feet, respectively.

Step-by-step explanation:

Let the scale be $4\,in\,:\,5\,ft$ and the dimensions of the rectangle being 4 inches and 5 inches, respectively. The scale ( $r$ ), measured in inches per feet, is equivalent to the following rational number:

$r = \frac{4\,in}{5\,ft}$

We can convert each length by dividing it by scale factor. That is:

Length

$l' = \frac{16\,in}{\frac{4\,in}{5\,ft} }$

$l' = 20\,ft$

Width

$w' = \frac{25\,in}{\frac{4\,in}{5\,ft} }$

$w' = 31.25\,ft$

The length and width of the rectangle are 20 feet and 31.25 feet, respectively.

8 0

3 years ago