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3 years ago

AREA How do you write1/2 as a percentage? Write your answer using a percent sign (%)

Mathematics

2 answers:

dexar [7]3 years ago

3 0

Answer:

50%

Step-by-step explanation:

1 is half of 2 and 50% of anything is half

bonufazy [111]3 years ago

3 0

Answer:

give me brainllest if i am right

50%

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What is the total weight of 7 penciles

Mamont248 [21]

Answer:

0.2 - 0.3 pounds

Step-by-step explanation:

Well because I dont know much information about the weight and background of the pencils. My answer may not be correct. But the average weight would be around 0.2 - 0.3 lbs.

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3 years ago

The sales of digital cameras (in millions of units) in year t is given by the function

erma4kov [3.2K]

Digital Cameras Sold more

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3 years ago

Read 2 more answers

36 percent of what is 99

mariarad [96]

Let the number be x,

(x*36)/100 = 99

x*36 = 9900

x= 9900/36

x=275

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3 years ago

The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.80. It is also known that P(A1 ∩ A2) = 0. Suppose P(

Umnica [9.8K]

Answer:

(a) $A_1$ and $A_2$ are indeed mutually-exclusive.

(b) $\displaystyle P(A_1\; \cap \; B) = \frac{1}{20}$ , whereas $\displaystyle P(A_2\; \cap \; B) = \frac{1}{25}$ .

(d) $\displaystyle P(A_1 \; |\; B) \approx \frac{5}{9}$ , whereas $P(A_1 \; |\; B) = \displaystyle \frac{4}{9}$

Step-by-step explanation:

$P(A_1 \; \cap \; A_2) = 0$ means that it is impossible for events $A_1$ and $A_2$ to happen at the same time. Therefore, event $A_1$ and $A_2$ are mutually-exclusive.

By the definition of conditional probability:

$\displaystyle P(B \; | \; A_1) = \frac{P(B \; \cap \; A_1)}{P(B)} = \frac{P(A_1 \; \cap \; B)}{P(B)}$ .

Rearrange to obtain:

$\displaystyle P(A_1 \; \cap \; B) = P(B \; |\; A_1) \cdot P(A_1) = 0.25 \times 0.20 = \frac{1}{20}$ .

Similarly:

$\displaystyle P(A_2 \; \cap \; B) = P(B \; |\; A_2) \cdot P(A_2) = 0.80 \times 0.05 = \frac{1}{25}$ .

Note that:

$\begin{aligned}P(A_1 \; \cup \; A_2) &= P(A_1) + P(A_2) - P(A_1 \; \cap \; A_2) = 0.20 + 0.80 = 1\end{aligned}$ .

In other words, $A_1$ and $A_2$ are collectively-exhaustive. Since $A_1$ and $A_2$ are collectively-exhaustive and mutually-exclusive at the same time:

$\displaystyle P(B) = P(B \; \cap \; A_1) + P(B \; \cap \; A_2) = \frac{1}{20} + \frac{1}{25} = \frac{9}{100}$ .

By Bayes' Theorem:

$\begin{aligned} P(A_1 \; |\; B) &= \frac{P(B \; | \; A_1) \cdot P(A_1)}{P(B)} \\ &= \frac{0.25 \times 0.20}{9/100} = \frac{0.05 \times 100}{9} = \frac{5}{9}\end{aligned}$ .

Similarly:

$\begin{aligned} P(A_2 \; |\; B) &= \frac{P(B \; | \; A_2) \cdot P(A_2)}{P(B)} \\ &= \frac{0.05 \times 0.80}{9/100} = \frac{0.04 \times 100}{9} = \frac{4}{9}\end{aligned}$ .

6 0

3 years ago

The poorest person in a country has 50$ and the richest had $9.956. How much less money does the poorest have

Alecsey [184]

What you need to do is subtract since the key word "How much Less money" is in it.

$9.956-$50 = 40.044$

4 0

3 years ago

AREA How do you write1/2 as a percentage? Write your answer using a percent sign (%)​

AREA How do you write1/2 as a percentage? Write your answer using a percent sign (%)