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Vladimir [108]
3 years ago
8

00:36:46

Mathematics
1 answer:
miskamm [114]3 years ago
4 0

Question:

In some code, letters a, b, c, d and e represent numbers 2, 4, 5, 6 and 10. We just do not know which letter represents which number. Consider the following relationships:

a + c = e,

b – d = d and

e + a = b

Which of the following statements is true?

(A) b = 4, d = 2

(B) a = 4, e = 6

(C) b = 6, e = 2

(D) a = 4, c = 6

Answer:

(B) a = 4, e = 6 is the correct answer.

Explanation:

(A) b = 4, d = 2

a + c = e => a + c = e

b – d = d => 4 - 2 = 2

e + a = b => e + a = 4

We are not able to find out what will be at place of a , c , e by which all other relationships are not getting satisfied. And if we apply numbers by hit and trial they are not getting satisfied.

(B) a = 4, e = 6

a + c = e => 4 + c = 6 => 4 + 2 = 6

b – d = d => b - d = d => 10 - 5 = 5

e + a = b => 6 + 4 = 10

We were able to find all a , b , c , d , e and it satisfies all relationships given.

(C) b = 6, e = 2

a + c = e => a + c = 2

b – d = d => 6 - d = d

e + a = b => e + a = 6

We are not able to find out what will be at place of a , c , d by which all other relationships are not getting satisfied. And if we apply numbers by hit and trial they are not getting satisfied.

(D) a = 4, c = 6

a + c = e => 4 + 6 = 10

b – d = d => b - d = d

e + a = b => e + 4 = b => 10 + 4 = 14(this is not from the numbers as given in question so b can't be equal to 14)

We got stuck at the value of b which was 14 and not given in question so, we can leave this option in between as it is not satisfying the relationships.

Therefore, (B) a = 4, e = 6 is the correct answer.

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Answer:

Do not reject H0. The mean days surfed for longboarders is significantly larger than the mean days surfed for all shortboarders

Step-by-step explanation:

The null hypothesis is that  the mean days surfed for all long boarders is larger than the mean days surfed for all short boarders

H0:  μL > μs      against the claim Ha:  μL≤ μs

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