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Nina [5.8K]
3 years ago
12

✨I NEED A SMART PERSON✨ (math)

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
4 0
All I know is A and E are one of them
Tems11 [23]3 years ago
3 0

Answer:

A and E.

Step-by-step explanation:

Using the math from 7th grade, 6 rooted is 36/9=4+10 is 14. Everything else you must multiply everything in parenthesis, by the outside number, then you add them. E is right because -15+35=20-6=14. Yw.

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Answer:

what are the answers for a b c and d

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John lives on the side of a mountain and the elevation of his residence is 1025 feet above sea level. His brother lives in a dee
aliina [53]
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PLEASE HELP!
hammer [34]

Answer:

  A = 16

Step-by-step explanation:

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6 0
3 years ago
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Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y
irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

y'(x)= x^2y(x)-\frac12y^2(x)

Putting the value of y'(x) in equation (1)

y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))

Substituting x =0 and h= 0.2

y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]

\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]    [∵ y(0) =3 ]

\Rightarrow y(0.2)\approx 2.7

Substituting x =0.2 and h= 0.2

y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]

\Rightarrow y(0.4)\approx  2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]

\Rightarrow y(0.4)\approx 1.9926

Substituting x =0.4 and h= 0.2

y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]

\Rightarrow y(0.6)\approx  1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]

\Rightarrow y(0.6)\approx 1.6593

Substituting x =0.6 and h= 0.2

y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]

\Rightarrow y(0.8)\approx  1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]

\Rightarrow y(0.6)\approx 0.8800

Substituting x =0.8 and h= 0.2

y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]

\Rightarrow y(1.0)\approx  0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]

\Rightarrow y(1.0)\approx 0.9152

Therefore the value of y(1)= 0.9152.

4 0
3 years ago
A circular garden has a circumference of 42.3 feet. Find the approximate diameter of the garden. Use 3.14 for π.
tamaranim1 [39]

Answer:

13.5

Step-by-step explanation:

c = 2πr

42.3 = 2(3.14)r

42.3 = 6.28r

6.74 = r

d = r + r

d = 6.74 + 6.74

d = 13.5

6 0
2 years ago
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