Answer:
where is the picture???????????????
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
<h2><em>2</em><em>x</em><em>-</em><em>6</em><em>+</em><em>1</em><em>5</em><em>x</em><em>+</em><em>5</em><em>-</em><em>1</em><em>6</em><em>x</em><em>=</em><em>x</em></h2>
<h2><em>2</em><em>x</em><em>+</em><em>1</em><em>5</em><em>x</em><em>-</em><em>1</em><em>6</em><em>x</em><em>-</em><em>x</em><em>=</em><em>6</em><em>-</em><em>5</em></h2><h2 /><h2 /><h2><em>0</em><em>×</em><em>x</em><em>=</em><em>1</em></h2><h2 /><h2 /><h2 /><h2><em>x</em><em>=</em><em>1</em><em>÷</em><em>0</em></h2><h2 /><h2 /><h2><em>x</em><em>=</em><em>0</em></h2>
The liters in the tank when it is filled to a height of 3.70 is 5,580 liters
The liters that needs to be added to 100% capacity is 480 liters
<h3>What is the volume?</h3>
A right circular cone is a three dimensional object has a flat circular base that tapers to a vertex. The volume of a right circular cone is the amount of space in the right circular cone.
Volume of a cone = 1/3(πr²h)
Where:
- π = pi = 3.14
- r = radius
- h = height
Volume of the right circular cone when its filled to a height of 3.70 = 1/3 x 3.14 x 3.70 x 1.20² = 5.58 m³
5.58 x 1000 = 5,580 liters
Volume of the right circular cone when it is full = 1/3 x 3.14 x 4 x 1.20² = 6.03 m³
6.03 x 1000 = 6030 liters
Liters that needs to be added to 100% capacity = 6030 liters - 5,580 liters = 480 liters
To learn more about the volume of a cone, please check: brainly.com/question/13705125
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Answer:
The correct answer is C
Step-by-step explanation:
Answer:
<h3>The value of
is
</h3><h3>The value of
is
</h3><h3>The partial derivative at s=-5 and t=10 is
is
</h3><h3>The partial derivative at s=-5 and t=10 is
</h3>
Step-by-step explanation:
Given that the Function point are 
, 
and s = -5, t = 10
<h3>To find
and
using the appropriate Chain Rule :
</h3>
Substitute the values of x and y in the above equation we get
<h3>Now partially differentiating w with respect to s by using chain rule we have
</h3>
<h3>Therefore the value of
is
</h3>
<h3>Now partially differentiating w with respect to t by using chain rule we have
</h3>
<h3>Therefore the value of
is
</h3>
Now put s-5 and t=10 to evaluate each partial derivative at the given values of s and t :
<h3>Therefore the partial derivative at s=-5 and t=10 is
is
</h3>
<h3>Therefore the partial derivative at s=-5 and t=10 is
</h3>
