Need help fast please with these 5 questions

Mathematics

1 answer:

vredina [299]3 years ago

6 0

Answer:

1. n = -5

2. n = 6

3. n = 3

4. n = 5

5. n = 0

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If someone tells you the public debt is 1.258x 10 to the 13 dollars, how much money is that

stellarik [79]

12.58 dollars. Hope this helps

4 0

3 years ago

Can u help me plz and thank u

Elan Coil [88]

Answer:

Step-by-step explanation:

∠CBA + ∠ABD = 180 {linear pair}

2x - 6 + x +1 = 180

3x -5 = 180

3x = 180 +5

3x = 185

x = 185/3

x = 61 2/3

$2x-6=2*61\frac{2}{3}-6\\\\=2*\frac{185}{3}-6\\\\=\frac{370}{3}-\frac{18}{3}\\\\=\frac{352}{3}=117\frac{1}{3}$

6 0

3 years ago

Please HELPPPP me !!!!!

dedylja [7]

Answer:

$y = 4x - 3\\Slope \ m_1 = 4$

EQUATION OF LINE PERPENDICULAR

$Lines \ are \ perpendicular => m_1 \cdot m_2 = -1\\$

$slope, m_2 = \frac{-1}{4}$

$equation \ of \ the\ line \ passing \ through \ (-2, 2) \ slope ,m_2 :\\(y - y_2) =m_2(x - x_2)\\ (y - 2) = \frac{-1}{4} (x -(-2))\\\\y - 2 = \frac{-1}{4} (x +2)\\\\y = \frac{-1}{4}x - \frac{1}{2} + 2\\\\y = \frac{-1}{4}x + \frac{3}{2}$

EQUATION OF LINE PARALLEL

$Lines \ are \ parallel => m_1 \cdot m_3 = 1\\slope, m_3 = \frac{1}{4}$ $Equation \ of \ the \ line \ through \ (-2, 2) \ and \ slope, m_3:\\(y - y_3) =m_3(x - x_3)\\\\(y-2) = \frac{1}{4} (x - (-2))\\\\y-2 = \frac{1}{4}(x+2)\\\\y = \frac{1}{4}x + \frac{1}{2} +2\\\\y = \frac{1}{4}x + \frac{5}{2}$