N² - 49 = 0
<u> + 49 + 49</u>
n² = 49
n = <u>+</u>7
The solution to the problem is {7, -7}.
Answer:
2a²
Step-by-step explanation:
Pair 'like' terms with 'like' terms, ie numbers go with numbers, and 'a's go with 'a's.
Lets deal with the top of the fraction first:
4ax3a³
Rearrange it so you have numbers beside numbers and 'a's beside 'a's:
(4x3)x(axa³)
12x(a⁴) <em>(because nᵃxnᵇ=nᵃ⁺ᵇ)</em>
12a⁴
Now, instead of (4ax3a³)/6a², we have 12a⁴/6a²
First divide the numbers: 12/6 =2
Now divide the 'a' parts: a⁴/a²=a² <em>(because nᵃ/nᵇ=nᵃ⁻ᵇ)</em>
Now we have 2a²
Answer:
a = 10, b = 6, c = 2, d = 0
Step-by-step explanation:
Substitute the appropriate values of x into the equation and evaluate
x = - 3 : y = 4 - 2(- 3) = 4 + 6 = 10 → a
x = - 1 : y = 4 - 2(- 1) = 4 + 2 = 6 → b
x = 1 : y = 4 - 2(1) = 4 - 2 = 2 → c
x = 2 : y = 4 - 2(2) = 4 - 4 = 0 → d
Answer:
cos theta=8/17
8/17=A/H
finding O,
O ² + A² =H ²
(8)²+O²=(17)²
64+O²=289
O²=289-64
O²=225
O=√225
O=15
we know that H=17, A=8, O=15
therefore, the other trigonometric ratios are
sinФ=O/H=15/17
tanФ=O/A=15/8
cosecФ=H/O=17/15
secФ=H/A=17/8
cotФ=A/O=8/15
hope it helps u!
