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wariber [46]
3 years ago
15

- 4(x + 3) = -12 – 4x

Mathematics
1 answer:
Elina [12.6K]3 years ago
5 0

Answer:

Interval Notation:

( − ∞ , ∞ )

Step-by-step explanation:

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Can someone please help me??
olga2289 [7]
You would have to multiply then subtract
30% is .30
Multiply 18.75 and .30
which is $5.63
Then subtract 18.75 from 5.63
Which the final ANSWER is: $13.12
5 0
2 years ago
In a right triangle, CosA=0.352 and SinA=0.936 What is the approximate value of tanA?
mr_godi [17]
\tan A=\frac{\sin A}{\cos A}

Proof: \sin\div\cos=\frac{o}h\div\frac{a}h=\frac{o}h\times\frac{h}a=\frac{oh}{ha}=\frac{o}a=\tan

\cos A=0.352,\ \sin A=0.936

\tan A=\frac{0.936}{0.352}

\boxed{\tan A=2.65\overline{90}} <em>(round as needed)</em>
6 0
3 years ago
Read 2 more answers
Evaluate the expression. 5^2−4⋅6+11 Enter your answer in the box.
mart [117]

Explanation:

This question's it's about the order of operations. P-parenthesis, E-exponents, M-multiply, D-divide, A-add, and S-subtract. It can also go left to right.

Do exponents first.

5^2=5*5=25

25-4*6+11

Then, multiply left to right.

4*6=24

25-24+11

And add/subtract left to right.

25-24=1

1+11=12

\boxed{=12}

Hope this helps!

Thanks!

Have a great day!


6 0
2 years ago
In right triangle KLM, KL =14 and angle L=30° and angle M=90°. Find KM. Leave your answer in the simplest radical form.
salantis [7]

Answer:

KM = 7 Units

Step-by-step explanation:

In the given structure ΔKLM

∠KLM = 30° and side KL = 14 and ∠KML = 90°

and we have to find the measurement of KM.

From right angle triangle KLM

Side Sin30° = KM/KL = KM/14

KM = 14×sin30° = 14×1/2 = 7

So the answer is KM = 7 Units

5 0
3 years ago
Is the centre of a circle always equal distance from all points on the circumference? and why
AleksandrR [38]

Answer:

Yes, the center of a circle is always and always equidistant from all the points on circumference because that is because what a circle is called. The distance from the center of the circle to the circumference is called the radius and it is constant for any particular circle.

7 0
2 years ago
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