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3 years ago

Find the diameter, approximate circumference and area of the circle below. (Use 3 for π)

Mathematics

2 answers:

vovikov84 [41]3 years ago

5 0

Answer:

Circumference = 42

Area = 147 to the power of 2

Step-by-step explanation:

7x2=14 diameter

3x14=42 circumference

Area = 7x7x3 =147 to the power of 2

seraphim [82]3 years ago

4 0

Diameter=14
Circumference =43.98
Area=153.94

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To make purple plum paint, the paint store mixes blue and red paint in a ration of 8:5 if a customer needs 65 gallon of paint ho

Olegator [25]

Answer:

Number of gallons of blue paint = 40 gallons

Number of gallons of red paint = 25 gallons

Step-by-step explanation:

We are given the ratio:

Blue paint : Red paint =

8 : 5

Sum of proportion = 8 + 5 = 13

If the customer need 65 gallons of paint,

a) Number of gallons of blue paint needed =

8/13 × 65 gallons = 40 gallons

b) Number of gallons of red paint needed =

5/13 × 65 gallons = 25 gallons

Therefore:

Number of gallons of blue paint = 40 gallons

Number of gallons of red paint = 25 gallons

3 0

3 years ago

Identify the monomial function described as odd or even, and indicate whether a is positive or negative.

Igoryamba

Answer:

Case 1: As x > 0 increases, f(x) increases. As x < 0 decreases, f(x) decreases.

It is an 'odd' function with 'positive' a.

Case 2: As x > 0 increases, f(x) decreases. As x < 0 decreases, f(x) decreases.

It is an 'even' function with 'negative' a.

Case 3: As x > 0 increases, f(x) increases. As x < 0 decreases, f(x) increases.

It is an 'even' function with 'positive' a.

Case 4: As x > 0 increases, f(x) decreases. As x < 0 decreases, f(x) increases.

It is an 'odd' function with 'negative' a.

Step-by-step explanation:

Let us consider a monomial function:

f(x) = axⁿ

Case 1:

As x > 0 increases, f(x) increases. As x < 0 decreases, f(x) decreases.

This happens only if a is 'positive' and n is 'odd'. So, it is an 'odd' function with 'positive' a.

Case 2:

As x > 0 increases, f(x) decreases. As x < 0 decreases, f(x) decreases.

This happens only if a is 'negative' and n is 'even'. So, it is an 'even' function with 'negative' a.

Case 3:

As x > 0 increases, f(x) increases. As x < 0 decreases, f(x) increases.

This happens only if a is 'positive' and n is 'even'. So, it is an 'even' function with 'positive' a.

Case 4:

As x > 0 increases, f(x) decreases. As x < 0 decreases, f(x) increases.

This happens only if a is 'negative' and n is 'odd'. So, it is an 'odd' function with 'negative' a.

Keywords: monomial function, odd function, even function

Learn more about monomial function from brainly.com/question/8973176

#learnwithBrainly

3 0

3 years ago

Read 2 more answers

Is 38/58 in simplest form? Explain why or why not. If not, write it in simplest form

Fofino [41]

Both 38 and 58 are even so they both can be divided by 2,

38/58

19/29

that is in the simplest form

6 0

3 years ago

Read 2 more answers

Luke scored 21 goals in 7 games. if he scores goals at the same rate how many goals will he score in 23 games

Gre4nikov [31]

<span>Luke scored 21 goals in 7 games. if he scores goals at the same rate how many goals will he score in 23 games
</span>the answer is 69
you divide 21 by 7 which is 3 and you multiply 3 by 23 and you get 69

3 0

4 years ago

A particular variety of watermelon weighs on average 20.4 pounds with a standard deviation of 1.23 pounds. Consider the sample m

love history [14]

Answer:

a) The expected value of the sample mean weight is 20.4 pounds.

b)The standard deviation of the sample mean weight is 0.123.

c) There is a 14.46% probability the sample mean weight will be less than 20.27.

d) This value is $c = 20.6153$ .

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A particular variety of watermelon weighs on average 20.4 pounds with a standard deviation of 1.23 pounds. This means that $\mu = 20.4, \sigma = 1.23$

Consider the sample mean weight of 100 watermelons of this variety. This means that $n = 100$ .

a. What is the expected value of the sample mean weight? Give an exact answer.

By the Central Limit Theorem, it is the same as the mean of the population. So the expected value of the sample mean weight is 20.4 pounds.

b. What is the standard deviation of the sample mean weight? Give your answer to four decimal places.

By the Central Limit Theorem, that is:

$s = \frac{\sigma}{\sqrt{n}} = \frac{1.23}{\sqrt{100}} = 0.123$

The standard deviation of the sample mean weight is 0.123.

c. What is the approximate probability the sample mean weight will be less than 20.27?

This is the pvalue of Z when $X = 20.27$ .

Since we are working with the sample mean, we use $s$ instead of $\sigma$ in the Z score formula

$Z = \frac{X - \mu}{s}$

$Z = \frac{20.27 - 20.4}{0.123}$

$Z = -1.06$

$Z = -1.06$ has a pvalue of 0.1446.

This means that there is a 14.46% probability the sample mean weight will be less than 20.27.

d. What is the value c such that the approximate probability the sample mean will be less than c is 0.96?

This is the value of $X = c$ that is in the 96th percentile, that is, it's Z score has a pvalue 0.96.

So we use $Z = 1.75$

$Z = \frac{X - \mu}{s}$

$1.75 = \frac{c - 20.4}{0.123}$

$c - 20.4 = 0.123*1.75$

$c = 20.6153$

This value is $c = 20.6153$ .

6 0

3 years ago