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mash [69]
3 years ago
6

Which of the following is not a solution for finding the perimeter of the square?

Mathematics
1 answer:
kenny6666 [7]3 years ago
7 0

Answer:

y

Step-by-step explanation:

y needs to provide a number

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8 is 16% of what?<br> Complete the sentence
zalisa [80]

Answer:

50

Step-by-step explanation:

the answer is 50 becuz it is

3 0
2 years ago
For question 3, use the Pythagorean Theorem.
Juliette [100K]

Step-by-step explanation:

can't really use the Pythagorean because you don't know this is a right triangle.

use the fact that they are similar

so

3/6 = x/12 where x is FE

cross multiply

6x = 36 therefore FE = 6

then 6/12 = y/9 where y is FD

cross multiply

12y = 54 = 54/12 therefore FD = 4.5

3 0
3 years ago
No links pls
asambeis [7]

Answer:

Positive 1 over 6 raised to the 2nd power 1/62 or 1 over 36 which is 1/36. To find -6-2, take the inverse of -62.

(first find -62) -62 = -6 * -6 = 36

(then take the inverse of 36, which is 1 over 36) = 1 / 36 = 0.0277

so, -6-2 =0.0277

Step-by-step explanation:

3 0
3 years ago
Evaluate this expression for x=-5 and y=-5​
Talja [164]

Answer:

x - 2y=5

Step-by-step explanation:

Given

x = -5; y=-5

x - 2y --- missing from question

Required

Evaluate

We have:

x - 2y

Substitute for x and y

x - 2y=-5 - 2*-5

x - 2y=-5 +10

x - 2y=5

3 0
3 years ago
????⃗ (x,y)=(3x−4y)????⃗ +2x????⃗ F→(x,y)=(3x−4y)i→+2xj→ and ????C is the counter-clockwise oriented sector of a circle centered
Karolina [17]

By Green's theorem, the integral of \vec F along C is

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_D\left(\frac{\partial(2x)}{\partial x}-\frac{\partial(3x-4y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=6\iint_D\mathrm dx\,\mathrm dy

which is 6 times the area of D, the region with C as its boundary.

We can compute the integral by converting to polar coordinates, or simply recalling the formula for a circular sector from geometry: Given a sector with central angle \theta and radius r, the area A of the sector is proportional to the circle's overall area according to

\dfrac A{\frac\pi3\,\rm rad}=\dfrac{16\pi}{2\pi\,\rm rad}\implies A=\dfrac{8\pi}3

so that the value of the integral is

\dfrac{6\times8\pi}3=\boxed{16\pi}

6 0
3 years ago
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