Question

In ΔIJK, the measure of ∠K=90°, KJ = 65, IK = 72, and JI = 97. What is the value of the cosine of ∠J to the nearest hundredth?

Answer 1

Answer:

$\cos(J) = 0.67$

Step-by-step explanation:

Given

$\angle K = 90^o$

$KJ = 65$

$IK = 72$

$JI = 97$

Required

$\cos(J)$

The question is illustrated with the attached image.

From the image, we have:

$\cos(J) = \frac{KJ}{JI}$

This gives:

$\cos(J) = \frac{65}{97}$

$\cos(J) = 0.67010309278$

$\cos(J) = 0.67$ --- approximated