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const2013 [10]
3 years ago
11

PLEASE HELP ASAP BIG POINTS

Mathematics
2 answers:
Digiron [165]3 years ago
8 0

We are given the equation:

s(t) = gt² + v₀t + s₀

g=-4.9, v₀ =19.6 and s₀=24.5

plugging these values in the equation we get,

s(t)=-4.9t² +19.6t +24.5

Non when it hits the ground final height s(t) will be 0

0=-4.9t² +19.6t +24.5

first option is correct

spin [16.1K]3 years ago
8 0

Answer:

its A!!!

Step-by-step explanation:

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6 0
3 years ago
at a store, the probability that a customer buys socks is 0.15. the probability that a customer buys socks given that the custom
leva [86]

Answer: Option B

Step-by-step explanation:

First we assign a name to the events:

Event S: a customer buys socks

Event H: a customer buys shoes.

We know that :

P (S) = 0.15

We also know that the probability of S given that H occurs is:

P(S|H) =\frac{P(S\ and\ H)}{P(H)}=0.20

If two events S and H are independent then:

P (S) * P (H) = P (S\ and\ H)

This mean that if two events S and H are independent then:

P(S|H) =\frac{P(S)*P(H))}{P(H)}

P(S|H) =P(S)

We know that:

P(S|H) =0.20  and P (S) = 0.15

0.20\neq 0.15

This means that S and H events are dependent.

The answer is the option B

3 0
3 years ago
A 78 gram sample of Uranium loses half of its mass each year. What is the exponential equation? Please explain why A is the corr
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A

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8 0
2 years ago
The set of ordered pairs represents a
Murrr4er [49]

Answer:

The rule that represents the function is y=x^2+1 therefore the function is f(x)=x^2+1

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We have 5 ordered pairs in the plane xy. This means that <em>every pair has the form (x, y).</em>

Then, we have 5 values of x, which will give us 5 values of y, using the rule that represents the function.

<u>The easy evaluation is that when x=0, the value of y is y=1,</u> and then we can evaluate the rule for x=-1, and x=1, <em>the value of y is the same, y=2</em>. We can see here that we have a parabolic function, that is not centered in the origin of coordinates because when x=0, y=1.

So <u>we propose the rule </u>y=x^2+1<u> which is correct for the first 3 values of x.</u>

Now, <em>we evaluate the proposed rule when x=2, and when x=3</em>. This evaluations can be written as

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Therefore, the rule is correct, and the function is

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That was rude of him
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