Answer:
what is the selection for the first one???
Step-by-step explanation:
This is the concept of algebra, we are required to calculate the area cut out of a cylinder represented by the function x^2+z^2=36;
The equation of a circle is given by:
(x-a)^2+(y-b)^2=r^2
where;
(a,b) are the center of the circle;
r=radius of the circle
re-writing our equation we have:
x^2+z^2=36
(x-0)^2+(z-0)^2=6^2
this implies that the center of the circle is (0,0) and the radius is 6 units;
Therefore the area will be given by:
Area=πr^2
Area=π*6^2
Area=36π=113.1 sq. units
The answer is:

Further explanation:
Given expression is a radical expression. Radical expressions involve fractional exponents.
<u>Given:</u>
![\sqrt[4]{16}\ *\ \sqrt[4]{64}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%5C%20%2A%5C%20%5Csqrt%5B4%5D%7B64%7D)
Factorizing 16 and 64
![=\sqrt[4]{2*2*2*2}*\sqrt[4]{2*2*2*2*2*2}\\=\sqrt[4]{2^4} *\sqrt[4]{2^4*2^2}\\Can\ also\ be\ written\ as\\=\sqrt[4]{2^4} *\sqrt[4]{2^4}*\sqrt[4]{2^2}\\={(2^4)}^{\frac{1}{4}}*{(2^4)}^{\frac{1}{4}}*{(2^2)}^{\frac{1}{4}}\\=2*2*{(2)}^{\frac{1}{2} }\\=4*\sqrt{2}\\=4\sqrt{2}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B4%5D%7B2%2A2%2A2%2A2%7D%2A%5Csqrt%5B4%5D%7B2%2A2%2A2%2A2%2A2%2A2%7D%5C%5C%3D%5Csqrt%5B4%5D%7B2%5E4%7D%20%2A%5Csqrt%5B4%5D%7B2%5E4%2A2%5E2%7D%5C%5CCan%5C%20also%5C%20be%5C%20written%5C%20as%5C%5C%3D%5Csqrt%5B4%5D%7B2%5E4%7D%20%2A%5Csqrt%5B4%5D%7B2%5E4%7D%2A%5Csqrt%5B4%5D%7B2%5E2%7D%5C%5C%3D%7B%282%5E4%29%7D%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%2A%7B%282%5E4%29%7D%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%2A%7B%282%5E2%29%7D%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%5C%5C%3D2%2A2%2A%7B%282%29%7D%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%5C%5C%3D4%2A%5Csqrt%7B2%7D%5C%5C%3D4%5Csqrt%7B2%7D)
The answer is:

Keywords: Radical expressions, Square root
Learn more about radical expressions at:
#LearnwithBrainly
Answer:
5y3 without exponents would be 15.
the normal answer would be 15 y but they're no exponents.
Answer:
<h2>16.26</h2>
Step-by-step explanation:
Pythagorean Theorem | a^2 + b^2 = c^2
1) Plug in a & b
<h2>11^2 + 12^2 = c^2</h2>
2) Rewrite
<h2>c =

</h2>
3) Solve
<h2>c = 16.2788206</h2>
4) Round
<h2>16.26</h2>