Answer:
1.-12*(2r)^11 * (3s)
= -12*2048*3 r^11 s
= -73728 r^11 s
2.12C1 (2r)¹¹(-3s) = -36(2¹¹)r¹¹s = -73728r¹¹s
3.24 r - 36 s
The second term: -36 s
4.(2r-3s)^12
= (2r)^12 + 12C1 (2r)^11 (-3s)
= 2^12 r^12 + (12) 2^11 r^11 (-3) s
= 4096 r^12 - (12)(3)(2098) r^11 s
= 4096 r^12 - 73,728 r^11 s + .....
-73,728 r^11 s
Step-by-step explanation:
Yan lang po alam ko at nahirapan ako e solved yan hehe pero hope it helps
Answer:
I'm confused with this, I dont understand what you are asking.
Step-by-step explanation:
2 is equivalent with a lot of things,
1+1
3-1
92-90
7×7-47
4÷2
the list goes on...
Answer:
False
Step-by-step explanation:
Answer:
The correct option is x=3 , y=2
Step-by-step explanation:
According to the HL theorem if the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle then the triangles are congruent.
By using this theorem we can set up the system of equations as follows:
x=y+1 ...(1)
2x+3= 3y + 3 ..(2)
Now we will plug the value y+1 of equation 1 in equation 2.
2x+3 = 3y+3
2(y+1)+3=3y+3
2y+2+3=3y+3
2y+5=3y+3
Now combine the like terms:
5-3=3y-2y
2=y
y=2
Now plug the value y=2 in equation 1.
x=y+1
x=2+1
x=3
Thus the values of(x.y) are{(2,3)}
Therefore the correct option is x=3 , y=2 .....