<span>68=-16t2+64t+8
16t2-64t+60=0
4t2-16t+15=0
(2t-5)(2t-3)=0
t=5/2 or 3/2
The object is at 68 feet after 3/2 secs, and returns to 68 feet after another second..</span>
Answer: The ladder is 5.3 m long
Step by step solution
1. Draw out the scenario, ie a right triangle where the hypotenuse is the ladder, the wall is 4.5m and the angle the ladder and the ground makes 58 degree.
2. Soh, Cah, Toa
The wall is opposite, the ground is adjacent, and the ladder is hypotenuse
Sine (58) = 4.5/h
3. Solve for hypotenuse
h * sine (58) = 4.5
h = 4.5/sine (58)
h = ~ 5.3 m
The answer to your problem is 50b+8
The correct answer is one solution
Answer:
Infinite Solutions
Step-by-step explanation:
No math required since it is Infinite Solutions. :-)
