(2,5)(-1,8)
slope = (8 - 5) / (-1 - 2) = 3/-3 = -1
y - y1 = m(x - x1)
slope(m) = -1
(2,5)...x1 = 2 and y1 = 5
now we sub
y - 5 = -1(x - 2) <==
Answer:
X product of powers
Quotient of powers
Power of a power
X power of a product
Negative exponent
X zero exponent
Hope this helps ʕ•ᴥ•ʔ
Answer:
Follows are the solution to the given point:
Step-by-step explanation:
In point a:
¬∃y∃xP (x, y)
∀x∀y(>P(x,y))
In point b:
¬∀x∃yP (x, y)
∃x∀y ¬P(x,y)
In point c:
¬∃y(Q(y) ∧ ∀x¬R(x, y))
∀y(> Q(y) V ∀ ¬ (¬R(x,y)))
∀y(¬Q(Y)) V ∃xR(x,y) )
In point d:
¬∃y(∃xR(x, y) ∨ ∀xS(x, y))
∀y(∀x>R(x,y))
∃x>s(x,y))
In point e:
¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU (x, y, z))
∀y(∃x ∀z)>T(x,y,z)
∀x ∃z> V (x,y,z))
Step-by-step explanation:
Use exponent property of logs.
logb(x²) = 2 logb(x) = 2(0.49) = 0.98