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2 years ago

Math question please help if you get this right I will mark you as a brainliest

Mathematics

1 answer:

san4es73 [151]2 years ago

3 0

The Law of Cosines would be your best bet here, since the unknown side is opposite the known angle 110 degrees.

|AC|^2 = (8 in)^2 + (23 in)^2 - 2(8 in)(23 in)*cos 110 degrees

= 64 in^2 + 529 in^2 - (368 in^2)*(-0.342)

= 593 in^2 + 126 in ^2 approximately

= 719 in^2 approximately

Then the length of side AC is approx. √(716 in^2) = 27 in

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I think it’s A but again i’m not sure.

Gnoma [55]

M∠BDC=half the arc it faces=1/2 of 54=27
BD is the diameter, so m∠C=90
m∠DBC=180-90-27=63

6 0

3 years ago

What is 2/3 + __=1 4/9

g100num [7]

You turn 2/3 into 6/9
Then turn 1 4/9 into an improper fraction 13/9
Then subtract and you get 7/9

The answer is 7/9

4 0

2 years ago

Please I really need help:

Kobotan [32]

Hi there

The answer is
b.) y=8,000(1.14)^x

Good luck!

6 0

3 years ago

Read 2 more answers

Please someone what is the total surface area of this pryamid

Dimas [21]

Answer:

$\large\boxed{C.\ (25+25\sqrt3)\ in^2}$

Step-by-step explanation:

We have the square and four equilateral triangles.

The formula of an area of a squre:

$A_S=a^2$

a - length of side

The formula of an area of an equilateral triangle:

$A_T=\dfrac{a^2\sqrt3}{4}$

a - length of side

Clculate the areas:

SQURE:

$A_S=x^2\ in^2$

TRIANGLE:

$A_T=\dfrac{x^2\sqrt3}{4}\ in^2$

The SURFACE AREA of a square pyramid:

$S.A.=A_S+4A_T\\\\S.A.=x^2+4\cdot\dfrac{x^2\sqrt3}{4}=x^2+x^2\sqrt3$

Put x = 5:

$S.A.=5^2+5^2\sqrt3=(25+25\sqrt3)\ in^2$

7 0

3 years ago

Consider the following graph, which details the population of a city over time. A line graph titled Population (thousands) has y

Usimov [2.4K]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers