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nignag [31]
3 years ago
10

The areas of two rectangles can be represented by the functions shown. Which function represents the difference in the areas, h(

x) = f(x) – g(x)? h(x) = 4x2 – 4x – 11 h(x) = 4x2 – 4x + 11 h(x) = –4x2 + 4x + 11 h(x) = 4x2 – 4x – 9
Mathematics
2 answers:
alukav5142 [94]3 years ago
5 0

Answer:

<h3>x ^2 + 5x</h3>

Step-by-step explanation:

Let the area of the two triangles be expressed as;

f(x)= 4x^2+6x

g(x)=3x^2-x

Taking the difference

h(x) = f(x) - g(x)

h(x) = 4x ^2+6x - 3x^2-x

Collect like terms'

h(x) = 4x ^2 - 3x^2+6x-x

h(x) = x ^2 + 5x

Hence the difference is  x^2 + 5x

<em>Note that the functions were assumed. The same methos can be applied to any other given functions.</em>

<em />

Neko [114]3 years ago
4 0

Answer:

B: h(x) = 4x2 – 4x + 11

Step-by-step explanation:

I just did the assignmement on EDGEN and it's 200% correct!!

Also, heart and rate if you found this answer helpful. (P.S it makes me feel good to know that I helped someone today!!)

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AlekseyPX

Answer:

228 inches

Step-by-step explanation:

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3 years ago
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Please Solve this answer 9c+4=-23
nikitadnepr [17]
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6 0
3 years ago
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Find the equation of the tangent of x^2- xy + y^2 =7 at (-1, 2)
Citrus2011 [14]

Answer:

<u>It</u><u> </u><u>is</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>4</u><u>x</u><u> </u><u>+</u><u> </u><u>1</u><u>0</u>

Step-by-step explanation:

Let's first get the slope of the curve.

[ slope is the derivative of the equation ]

{x}^{2}  - xy +  {y}^{2}  = 7

introduce dy/dx :

\frac{d}{dx} ( {x}^{2}  - xy +  {y}^{2} ) =  \frac{d}{dx} (7) \\  \\ 2x - (y +  \frac{dy}{dx} ) + 2y \frac{dy}{dx}  = 0

make dy/dx the subject:

2x - y -  \frac{dy}{dx}  + 2y \frac{dy}{dx}  = 0 \\  \\ 2y \frac{dy}{dx}  -  \frac{dy}{dx}  = y - 2x \\  \\  \frac{dy}{dx} (2y - 1) = y - 2x \\  \\  \frac{dy}{dx}  =  \frac{y - 2x}{2y - 1}

At point (-1, 2):

\frac{dy}{dx}  =  \frac{2 - 2( - 1)}{2(2) - 1}  \\  \\ slope =  \frac{4}{3}

but a tangent has the same slope as the curve:

y = mx + c

m is the slope

c is the y-intercept

At (-1, 2):

2 = ( - 1 \times  \frac{4}{3} ) + c \\  \\ c = 2 +  \frac{4}{3}  \\  \\ c =  \frac{10}{3}

equation:

y =  \frac{4}{3} x +  \frac{10}{3}  \\  \\ { \boxed{3y = 4x + 10}}

8 0
3 years ago
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What is the slope of a line parallel to the line with equation 5x + 3y = 7?
weeeeeb [17]

Answer:

-5/3

Step-by-step explanation:

Parallel lines are lines which have the exact same slope but different y-intercepts. We can find the slope by converting to slope-intercept form, y=mx+b from standard form.

We convert by using inverse operations to isolate y.

5x+3y=7

5x-5x+3y=7-5x

0x+3y=-5x+7

3y=-5x+7

\frac{3y}{3} =\frac{-5x+7}{3} \\y=\frac{-5}{3}x+\frac{7}{3}.

The slope is -5/3. SInce parallel lines have the same slope, the slope for a parallel line will be -5/3.

3 0
4 years ago
Several terms of a sequence {an}n=1 infinity are given. A. Find the next two terms of the sequence. B. Find a recurrence relatio
s344n2d4d5 [400]

Answer:

A)\frac{1}{1024},\frac{1}{4096}

B) \left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.

C) \\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...

Step-by-step explanation:

1) Incomplete question. So completing the several terms:\left \{a_{n}\right \}_{n=1}^{\infty}=\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},... \right \}

We can realize this a Geometric sequence, with the ratio equal to:

q=\frac{1}{4}

A) To find the next two terms of this sequence, simply follow multiplying the 5th term by the ratio (q):

\frac{1}{256}*\mathbf{\frac{1}{4}}=\frac{1}{1024}\\\\\frac{1}{1024}*\mathbf{\frac{1}{4}}=\frac{1}{4096}\\\\\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},\mathbf{\frac{1}{1024},\frac{1}{4096}}\right \}

B) To find a recurrence a relation, is to write it a function based on the last value. So that, the function relates to the last value.

\left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.

C) The explicit formula, is one valid for any value since we have the first one to find any term of the Geometric Sequence, therefore:

\\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...

6 0
3 years ago
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