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Ket [755]
3 years ago
11

A postcard in the shape of a parallelogram has an area of 12in^2. What are two possible lengths of bases and heights for the pos

tcard
Mathematics
1 answer:
Tpy6a [65]3 years ago
8 0

A postcard is in the shape of a parallelogram. A parallelogram  is a quadrilateral with two pair of parallel sides, opposite sides and opposite angles are equal.

Since, the postcard has an area of 12 square inches.

Since, area of parallelogram = base \times height

As area of parallelogram is 12, it means that the product of base and height is 12 square inches.

So, the possible dimensions of postcard are 3 inches and 4 inches and 2 inches and 6 inches.

So, base = 3 inches , height = 4 inches or base = 4 inches , height = 3 inches.

So, base = 2 inches, height = 6 inches or base = 6 inches , height = 2 inches.

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A prism's volume is given by the expression 6k2 – 13k + 5. The area of the base of the prism is 2k – 1. Which expression represe
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The expression for the height is (3k - 5)
Factorise the equation 6k^2 - 13k + 5
One is given : (2k-1). When factorising, you must make sure that you are obtaining the given equation.
Here, to get 6k^2, 2k is multiplied with 3k. The other factor is (3k-x)
Now, let's find x. From the factors (2k-1) (3k-x) how to obtain 13k?? Simple...
3k×-1 + 2k×x = 13k
-3k + 2kx = 13k
-3k + 2k(-5) = -3k + -10k = 13k
So the other expression is (3k-5) which is the height.
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