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r-ruslan [8.4K]

2 years ago

7

Find the domain of fg. f(x) = x2 +1 g(x) = 1/x a. all real numbers c. all real numbers, except -1 b. all real numbers, except 0

d. all real numbers, except 1

1 answer:

ANTONII [103]2 years ago

3 0

Fg=f(x)g(x)=(x²+1)/x
The function fg is not defined if the denominator = 0 which means x can’t be 0
So B is the right answer to this question

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Mr. Smith wants to order some pizza and cheese pizza cost $11 and pepperoni pizza cost $12.50 if you bought 13 pieces total and

Triss [41]

Answer: Mr Smith bought 7 pepperoni pizza

Step-by-step explanation:

Step 1

cost of cheese pizza =$11

pepperoni pizza cost =$12.50

let number cheese pizza be represented as c

and number of pepperoni pizza be represented as p

such that the total number of pizza bought which equals 13 can be represented as

c+ p= 13

and total cost of both pizza can be expressed as

11c+ 12.50p =153.50

Step 2 Solving

c+ p= 13

11c+ 12.50p =153.50

By elimination method, Multiply equation 1 by 11 and subtract the new equation from equation 2

11c+ 12.50p =153.50

11c+ 11p=143.

1.5p =10.5

p= 10.5/ 1.5 =7

c+ p= 13

c= 13-p =13-7=6

Therefore Mr Smith bought 6 cheese pizza and 7 pepperoni pizza

6 0

2 years ago

E/4+2f-3 when e=12 and f =1/2

Viktor [21]

Answer:

$\frac{e}{4} + 2f - 3 \\ \frac{12}{4} + 2 \times \frac{1}{2} - 3 \\ 3 + \frac{2}{2} - 3 \\ 3 + 1 - 3 \\ 4 - 3 = 1$

6 0

3 years ago

PLS HELP ME Find a sum equivalent to the product shown. 5(x+z)

andrezito [222]

Answer:

20

Step-by-step explanation:

4 0

3 years ago

Can anyone please help me with this!!! :(

UkoKoshka [18]

Answer:

ano ba gagawin

parang Ang Dali pero ano gagawin dyan

3 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B80%7D%20" id="TexFormula1" title=" \sqrt[3]{80} " alt=" \sqrt[3]{80} " ali

Marianna [84]

Start by decomposing the number inside the root into primes

Then group the terms into cubes if possible

$\begin{gathered} 80=2\cdot2\cdot2\cdot2\cdot5 \\ 80=2^3\cdot2\cdot5 \\ 80=10\cdot2^3 \end{gathered}$

rewrite the root

$\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}$

then cancel the terms that are cubes and bring them out of the root

$\sqrt[3]{80}=2\sqrt[3]{10}$

7 0

1 year ago