The area of a triangle can be calculated as half the product of base length and height. We want the area to be no greater than 10 in².
a) (1/2)(4)(2x-3) ≤ 10
b) 4x -6 ≤ 10 . . . . . simplify
... 4x ≤ 16 . . . . . . . .add 6
... x ≤ 4 . . . . . . . . . divide by the coefficient of x
c) The maximum value of (2x -3) in is (2·4 -3) in = 5 in.
The triangle should be no more than 5 in high to have an area less than 10 in².
Answer:
from what we're given on the drawing, ac and pt are congruent
and from the question format, ab is equal to pq, ac is equal to pr
Answer:
Step-by-step explanation:
Answer:
x = 3, y = 1 is the solution of the given system.
Step-by-step explanation:
Here, the given system of equations is:
y = -x + 4 ...... (1)
y = x - 2 .......... (2)
Now, to find the solution of the system, SUBSTITUTE the value of y from equation (1) in to the equation (2). We get ,
y = x - 2 ⇒ -x + 4 = x - 2 ( as from (1), y = -x + 4)
or, -x -x = -2 -4
or, - 2 x = -6 ⇒ x = 6/2 = 3
or, x = 3
⇒ y = x - 2 = 3 - 2 = 1
⇒ y = 1
Hence, x = 3, y = 1 is the solution of the given system.
Cylinder volume = PI * radius^2 * height
cylinder volume = 3.14159 * 16 * 4
cylinder volume = 3.14159 * 64
cylinder volume =
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