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3 years ago

11

The triangle ABC is right angled at B. Its area is 64 cm². One side of the right angle measures 8 cm. Determine the length of th

e hypotenuse.

1 answer:

timama [110]3 years ago

5 0

Answer:

4 CM

You need to add then divide by 3

You need to add then divide by 3

You need to add then divide by 3

You need to add then divide by 3v

Step-by-step explanation:

You need to add then divide by 3

You need to add then divide by 3

You need to add then divide by 3v

You need to add then divide by 3You need to add then divide by 3

You need to add then divide by 3

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sandy had some pineapples at her house. she went to the store and bought 14 more. when she got home she had a total of 43 pineap

EleoNora [17]

She had 29 Pineapples

29+14=43

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4 years ago

Read 2 more answers

Write an equation of the Ferris WheelSydney wants to ride a Ferris wheel that has a radius of 60 feet and is suspended 10 feet a

zmey [24]

Answer:

a) $y (t) = 70 -60 cos[\frac{2pi}{3}(t)]$

b) $y (t=1.25) = 70 -60 cos[\frac{2pi}{3}(1.25)] =121.96 ft$

c) Is just a translation of th original graph.

$y (t) = 70 -60 sin[\frac{2pi}{3}(t)]$

Step-by-step explanation:

Data given

R= 60 ft represent the radius

D= 2*60 = 120 ft represent the diameter

Suspended x=10 ft above the ground

Rpm = 2 rev/6min = 1 rev/3 min

The friend start 1/4 after Sydney.

Part a

We can find the maximum and minimum point like this

$Max = 120+10 ft = 130ft$

$Min= 10 ft$

We add 10 ft to the maximum because we are 10 ft above the ground

Then we can find the amplitude:

$2A= Max-Min= 130-10 = 120 ft$

So then $A = 60 ft$

And the middle point would be given by:

$M=\frac{Max+Min}{2}=\frac{130+10}{2}=70 ft$

We have also the period given by $T = 3minutes$ since we have 1 revolution each 3 minutes.

We need to write a function that describes a Sydney’s height above the ground as a function of the number of seconds. So then we need to take the middle point 70 ft and subtract the function in terms of the amplitude and the period.

The the number of wave is given by $k = frac{2\pi}{T}=\frac{2\pi}{3}$

And the general equation would be given by:

$y (t) = 70 -A cos[\frac{2pi}{3}(t)]$

And replacing we got:

$y (t) = 70 -60 cos[\frac{2pi}{3}(t)]$

Part b

For this case we just need to replace t =1.25 min and we got:

$y (t=1.25) = 70 -60 cos[\frac{2pi}{3}(1.25)] =121.96 ft$

Part c

We need to take in count that the midpoint is at y=0. With the transofrmation we have the midpoint at y=70 ft. And if we move 1/4 we can see that the graph for the friend is the sine graph of the original equation.

And we can se this on the plot attached. When t=0 for the cos function is t=0.75 for the sin function. And the equation for the friend would be given by:

$y (t) = 70 -60 sin[\frac{2pi}{3}(t)]$

3 0

4 years ago

If F(x) = x-3, which of the following is the inverse of F(x)?

charle [14.2K]

Answer:

B

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = x - 3 ( add 3 to both sides )

y + 3 = x

change y back into terms of x, then

$f^{-1}$ (x) = x + 3 → B

8 0

3 years ago

Read 2 more answers

A marketing study was conducted to compare the mean age of male and femlae purchasers of a certain product. random and independe

notka56 [123]

Answer:

A. t ≥ 1.734

Step-by-step explanation:

Data given and notation

$\bar X_{m}=39.80$ represent the mean for the sample male

$\bar X_{f}=50.30$ represent the mean for the sample female

$s_{m}=10.040$ represent the sample standard deviation for the males

$s_{f}=13.215$ represent the sample standard deviation for the females

$n_{m}=10$ sample size for the group male

$n_{f}=10$ sample size for the group female

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for females is higher than the mean for males, the system of hypothesis would be:

Null hypothesis: $\mu_{f}-\mu_{m}\leq 0$

Alternative hypothesis: $\mu_{f} - \mu_{m}> 0$

We don't have the population standard deviation, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{f}-\bar X_{m})-\Delta}{\sqrt{\frac{s^2_{f}}{n_{f}}+\frac{\sigma^2_{m}}{n_{m}}}}$ (1)

And the degrees of freedom are given by $df=n_m +n_f -2=10+10-2=18$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

What is the test statistic?

With the info given we can replace in formula (1) like this:

$t=\frac{(50.3-39.80)-0}{\sqrt{\frac{13.215^2}{10}+\frac{10.040^2}{16}}}}=2.001$

Critical value

For this case since we have a right tailed test we need to look into the t distribution with 18 degrees of freedom a value that accumulates 0.05 of the area on the right, and on this case:

$t_{crit}=1.734$

And the rejection zone of the null hypothesis would be: A. t ≥ 1.734

For our case our calculated value is higher than the critical value so we have enough evidence to reject the null hypothesis at the 5% of significance.

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4 years ago

Juanelda's doctor has prescribed medication that she must take every 5 hours. She started the medication at 10:00

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Need more information there is no question being asked.

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4 years ago