Using it's concept, it is found that there is a:
- 0.6207 = 62.07% probability of selecting a cow.
- 0.0345 = 3.45% probability of selecting a horse.
- 0.3448 = 34.48% probability of selecting a goat.
- 0% probability of selecting a chicken.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem, there is a total of 18 + 1 + 10 + 0 = 29 animals, hence:
18/29 = 0.6207.
0.6207 = 62.07% probability of selecting a cow.
1/29 = 0.0345.
0.0345 = 3.45% probability of selecting a horse.
10/29 = 0.3448.
0.3448 = 34.48% probability of selecting a goat.
0/29 = 0.
0% probability of selecting a chicken.
More can be learned about the probability concept at brainly.com/question/15536019
The equation we use here is:
x is for the number of games he played on first day, y is the games on second day. The coefficients are the decimal form of percentages.
Simplify:
To find x we need to use the ratio. We have 85/100 as the first day's ratio and because the games needs to be whole, we can simplify this as 17/20. So in first day, he played at least 20 games and won 17 of them.
When we plug the 20 into the equation as x:
So he needs to play at least 30 games in order to get his score to 94%.