The answer should be E.
mark me brainliest
Its all up to you and how hard you are willing to work to get that may credits in one semester. But you could do it. Hope that helped!
Hi
(6-d)(d²-5+3d) = 6d²-30+18d-d³+5d-3d² = -d³+6d²-3d²+18d+5d-30
(6-d)(d²-5+3d) = -d³+3d²+23d-30
Answer: -d³+3d²+23d-30
(x^2-3x+2)-1(3x^2-5x-1)=
x^2-3x+2-3x^2+5x+1=
x^2-3x^2-3x+5x+2+1=
-2x^2+2x+3
