Answer:
yes
Step-by-step explanation:
if you distribute the 9 into the parenthesis you get 9y + 45. Therefore, both equations are equivalent seeing that they both equal to 9y + 45.
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
Answer:
I choose option c hope it helps
I would be able to but i left my maths book at school and that has the explanation in, sorry :(
Answer:
1) y = (x + 8)² + 7; 5) y = (x - 6)² + 10; 7) y = (x - 3)² - 4
Step-by-step explanation:
Complete the square in order to figure these out. To complete the square, use the formula <em>[½B]</em><em>²</em><em>.</em><em> </em>Each time you do this, you get a perfect trinomial in the form of a product of two monomials [<em>h</em>], then you have to figure out how much more to deduct from or add on to your <em>C</em><em> </em>they gave you in each exercise [<em>k</em>].
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