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2 years ago

BRAINLIEST! ANSWER MY LATEST QUESTION FOR BRAINLIEST ON THIS AND THAT QUESTION! MUST BE CORRECT THO

Mathematics

2 answers:

Sloan [31]2 years ago

8 0

Answer:

Ok dude, chill

Step-by-step explanation:

Dimas [21]2 years ago

5 0

Answer:

whats the question?????

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2 years ago

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2 years ago

Derek found a function that approximately models the population of iguanas in a reptile garden, where x represents the number of

serious [3.7K]

Answer:

$i(x)=12 \times (1+\frac{0.9}{12})^{12x}$ and growth rate factor is 0.075

Step-by-step explanation:

The function that models the population of iguanas in a reptile garden is given by $i(x)=12 \times (1.9)^{x}$ , where x is the number of years.

Since, $i(x)=12 \times (1.9)^{x}$

i.e. $i(x)=12 \times (1+0.9)^{x}$ .

Therefore, the monthly growth rate function becomes,

i.e. $i(x)=12 \times (1+\frac{0.9}{12})^{x \times 12}$ .

i.e. $i(x)=12 \times (1+\frac{0.9}{12})^{12x}$ .

Hence, the monthly growth rate is i.e. $i(x)=12 \times (1+\frac{0.9}{12})^{12x}$ .

Also, the growth factor is given by $\frac{0.9}{12}$ = 0.075.

Thus, the growth factor to nearest thousandth place is 0.075.

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3 years ago