A brand of popcorn instructs users to microwave for 90–120 seconds on high. A student wonders what the ideal microwave time for
2 answers:
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the cost of labour per hour is $7.20
the cost of raw materials per pound is $11.60
Explanation:For product one:
time = 5 hours of labour
let the cost labour per hour = x
Amount = 3 pounds of raw amterials
let the cost of one pound raw material = y
Cost to produce each product = $70.8
The equation:
time (cost per hour) + amount (cost of one pound of raw material) = Cost to produce each product
5(x) + 3(y) = 70.80
For product 2:
time = 3.5 hours of labour
let the cost of labour per hour = x
Amount = 13 pounds of raw amterials
let the cost of one pound raw material = y
Cost to produce each product = $176.00
The equation:
time (cost per hour) + amount (cost of one pound of raw material) = Cost to produce each product
3.5(x) + 13(y) = 176
combining both equations:
5x + 3y = 70.8 ...(1)
3.5x + 13y = 176 ....(2)
Using elimination method:
To eliminate y, we will multiply equation (1) by 13 and equation (2) by 3 so that both coefficient of y become the same
65x + 39y = 920.4 ...(*1)
10.5x + 39y = 528 ...(2*)
subtract equation (2*) from (1*):
65x - 10.5x + 39y - 39y = 920.4 - 528
54.5x + 0 = 392.4
54.5x = 392.4
divide both sides by 54.5:
x = 392.4/54.5
x = 7.2
substitute for x in any of the equations
Using equation 1: 5x + 3y = 70.8
Hence, the cost of labour per hour is $7.20 and the cost of raw materials per pound is $11.60
<h3>Answer: (-1, 11)</h3>
This means x = -1 and y = 11 pair up together.
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Work Shown:
Set the two functions equal to one another. Solve for x.
f(x) = g(x)
-4x+7 = 2x+13
7 = 2x+13+4x ... adding 4x to both sides
7 = 6x+13
7-13 = 6x .... subtract 13 from both sides
-6 = 6x
6x = -6
x = -6/6 ... divide both sides by 6
x = -1
Use this x value in either function
f(x) = -4x+7
f(-1) = -4(-1)+7
f(-1) = 11
or
g(x) = 2x+13
g(-1) = 2(-1)+13
g(-1) = 11
Whichever function you pick, the input x = -1 leads to the output y = 11.
The point of intersection is (x,y) = (-1, 11)
Visual confirmation is shown below.