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siniylev [52]
3 years ago
14

Please answer CORRECTLY !!!!!!! Will mark BRAINLIEST !!!!!!!!!

Mathematics
1 answer:
Usimov [2.4K]3 years ago
8 0

Answer:

Maybe f(a) = 0.5b?

But it's not in terms of a.

Step-by-step explanation:

Simplify the equation:

-4a = -2b

a = 0.5b

Idk what next...

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Subtract (9.6x10^9)-(8.9x10^9)
KengaRu [80]

Answer:

(9.6x10^9)-(8.9x10^9) = 7×10^8

Step-by-step explanation:

7 0
3 years ago
Trump or Biden. <br> I'm curious. Please no fightin and i'll make brainlest
Oksana_A [137]

Answer:

Biden

Step-by-step explanation: Well I mean Trump done many racist, and mess up stuff so my only choice would be Biden and well hopefully  he doesnt  do the same thing as Trump

5 0
3 years ago
1 point
-Dominant- [34]
39
Divide 78 by 2 to get 39 and add in to the number
5 0
4 years ago
Karen has $1.70 in coins. Karen has 8 coins, all of which are quarters or dimes.
kumpel [21]

x+y=8 and 25x+10y=170 are the linear equations.

x+y≤8 and 25x+10y≤170 are the inequalities.

Step-by-step explanation:

Given,

Worth of coins = $1.70 = 1.70*100 = 170 cents

Number of coins = 8

1 quarter = 25 cents

1 dime = 10 cents

Let,

x represent the number of quarters

y represent the number of dimes

1. Write an equation to represent the amount of coins Karen has.

x+y = 8

2.Write an equation to represent the value of the coins Karen has.

25x+10y=170

x+y=8 and 25x+10y=170 are the linear equations.

For inequalities, the amount cannot increase number of coins and worth but it can be less, therefore,

x+y≤8

25x+10y≤170

x+y≤8 and 25x+10y≤170 are the inequalities.

Keywords: linear equations, addition

Learn more about linear equations at:

  • brainly.com/question/10570041
  • brainly.com/question/10610299

#LearnwithBrainly

4 0
4 years ago
Prove the following statements: (a) For every integer x, if x is even, then for every integer y, xy is even. (b) For every integ
Murrr4er [49]

Answer and Step-by-step explanation:

(a) Given that x and y is even, we want to prove that xy is also even.

For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.

(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:

Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.

(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.

3 0
3 years ago
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