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2 years ago

Find the value of the missing coefficient a in the equation y = a(x - 3)(x + 5) if the graph goes through the point (1, -6)

Mathematics

2 answers:

erik [133]2 years ago

6 0

Answer:

missing coffecient is 8

Iteru [2.4K]2 years ago

3 0

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

y-(a*(x-3)*(x+5))=0

STEP
1
:
Equation at the end of step 1

y - (a • (x - 3) • (x + 5)) = 0
STEP
2
:
Equation at the end of step 2

y - a • (x - 3) • (x + 5) = 0
STEP
3
:
Equation at the end of step 3

y - ax2 - 2ax + 15a = 0
STEP
4
:

Solving a Single Variable Equation:

4.1 Solve y-ax2-2ax+15a = 0

In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.

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Number 4, it would help this is a final

docker41 [41]

Answer:

-1.3 and 1.55

Step-by-step explanation:

7 0

3 years ago

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Can anyone solve this?

lesantik [10]

Answer:

44,280

Step-by-step explanation:

I might know. I multiplied the 1st and got 307.5.

then multiplied the 2d. I got 144

multiplied 307.5x144 and I got 44,280

7 0

1 year ago

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A triangle has an area of 48 square units. Its height is 8 units.

Sloan [31]

Area of triangle= 1/2(bh)
So u do the reverse to find the base
48 x 2 which equals 96
Then u divide
96 divided by 8 = 12
Length of base equals 12

5 0

2 years ago

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Need help on this!!!

Helga [31]

Answer:

Step-by-step explanation:

Range goes from the lowest point on a graph to the highest point, not including anything in between those 2 extremes. We will evaluate the quadratic for the values given. First f(2):

$f(2)=(2)^2-5$ so

f(2) = -1

Now, f(4):

$f(4)=(4)^2-5$ so

f(4) = 11

Now, f(7):

$f(7)=(7)^2-5$ so

f(7) = 44

The lowest y value is -1 and the highest is 44, so the range is from -1 to 44 (I can't tell which of your choices reflects that because it's too small!)

4 0

2 years ago

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

4 0

2 years ago