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Andru [333]
3 years ago
7

the length of a rectangle is 6.7 cm more than 2 times the width. If the perimeter of the rectangle is 57.2 cm, what are its dime

nsions?
Mathematics
1 answer:
ss7ja [257]3 years ago
6 0
57.2-6.7-6.7=43.8
43.8÷6=7.3
7.3×2+6.7=21.3
length = 21.3cm
width = 7.3cm
(21.3×2)+(7.3×2) = 57.2
hope that helps
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8{(5*3)+(2*5)+(2*10)=
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Answer:

8(5*3)+(2*5)+(2*10)=360

Step-by-step explanation:

8(15)+(10)+(20)=

8(45)=

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Jim borrowed $12,500 at 6% per annum compound interest . At the end of the first year ,he repaid $5,500.
Alika [10]

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6 0
4 years ago
If the sum of the legs of a right triangle is 49 inches and the hypotenuse is 41 inches, find the length of the other two sides
german
The length of one leg is x inches.
The sum of the legs is 49 inches, so the length of the other leg is 49-x inches.
The length of the hypotenuse is 41 inches.

Use the Pythagorean theorem:
(\hbox{one leg})^2 + (\hbox{the other leg})^2=(\hbox{hypotenuse})^2 \\ x^2+(49-x)^2=41^2 \\
x^2+2401-98x+x^2=1681 \\
2x^2-98x+2401=1681 \ \ \ |-1681 \\
2x^2-98x+720=0 \\ \\
a=2 \\ b=-98 \\ c=720 \\ b^2-4ac=(-98)^2-4 \times 2 \times 720=9604-5760=3844 \\ \\
x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-(-98) \pm \sqrt{3844}}{2 \times 2}=\frac{98 \pm 62}{4} \\
x=\frac{98-62}{4} \ \lor \ x=\frac{98+62}{4} \\
x=\frac{36}{4} \ \lor \ x=\frac{160}{4} \\
x=9 \ \lor \ x=40


49-x=49-9 \ \lor \ 49-x=49-40 \\
49-x=40 \ \lor \ 49-x=9

The lengths of the legs are 9 inches and 40 inches.
4 0
4 years ago
How do you do 8b+12-b=8+7b+4 and plz show how you got it
lawyer [7]
8b+12-b=8+7b+4
7b+12=12+7b
                 -7b
7b-7b+12=12
          -12   -12
0= 12-12
0=0
6 0
3 years ago
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