1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Svetllana [295]
2 years ago
10

What is the slope for the equation: y = - 4x + 5?

Mathematics
1 answer:
Iteru [2.4K]2 years ago
8 0

Answer:

m = − 4

Step-by-step explanation:

i got this correct

You might be interested in
Find the average of -4, -8, -12, 0, and -6.
nataly862011 [7]
Answer:
-6


To find the average, you first have to add each of your numbers.

(-4)+(-8)+(-12)+(0)+(-6)

-30

Next, you have to divide it by the number of terms

-30/5


Your answer is -6
6 0
2 years ago
Angle A and angle B are supplementary angles, if angle B equals 73°, what is the measurement of angle A?
balandron [24]
Supplementary means adds to 180
A+B=180
B=73
A+73=180
minus 73 both sides
A+73-73=180-73
A+0=107
A=107

A=107 degrees
7 0
2 years ago
Read 2 more answers
A wheel has a radius of 12 cm. Approximately how far does it travel in 2 revolutions?
pishuonlain [190]
150.72 cm is your answer 
7 0
2 years ago
Read 2 more answers
Help mee !! I’ll give points !!
exis [7]

Answer: It is (x - 3)(x + 5)

6 0
3 years ago
1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6
meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

<u>2x-2y=-6     </u>

<u>7x        =-21</u>

x= -3

Putting value of x in equation 1  

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

Let

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right] = A  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = X  and  \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]= B

Then AX= B

or X= A⁻¹ B

where  A⁻¹= adj A/ ║A║   where mod A≠ 0

adj A=  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]   \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14     \left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc}42\\0\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-3\\0\\\end{array}\right]

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0
3 years ago
Other questions:
  • Kinesha collects data about the height of students in her science class. What measure of a center and variation are appropriate
    14·2 answers
  • Juan has a cellular phone that costs a base fee of $12.95 plus 25° per minute for
    7·1 answer
  • Given: The measure of arc EY = The measure of arc YI, m∠EXY = 80°, and m∠K = 25°.
    5·2 answers
  • Identify the dependent and independent variables: bicep size and the amount of time spent weightlifting at the gym. Choose all t
    7·1 answer
  • Which function has an inverse that’s also a function?
    5·2 answers
  • What would the perfect square be???
    11·2 answers
  • Anyone wanna play Splatoon 2?<br><br><br> (if no then don't answer}
    11·2 answers
  • Hi please help, timed test!​
    14·1 answer
  • Which of the following is a radical equation?
    13·1 answer
  • 2.5 kg cost £1.40<br><br>work out the cost of 4.25kg
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!