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Svetllana [295]
3 years ago
10

What is the slope for the equation: y = - 4x + 5?

Mathematics
1 answer:
Iteru [2.4K]3 years ago
8 0

Answer:

m = − 4

Step-by-step explanation:

i got this correct

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20,000,000+400,000+80,000+4000+100+60+3
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Andy wrote the equation of a line that has a slope of Step 2: y plus 2 equals StartFraction 3 Over 4 EndFraction x minus StartFr
nlexa [21]

answer is C

He made an error in Step 3. He should have subtracted 2 from both sides.

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14.
Readme [11.4K]

The domain is t=0 to t=3.2  and range is y = 0 to 57.125 feet.

<u>What are Domain and range of a Function?</u>

  • The range of values that we are permitted to enter into our function is known as the domain of a function.
  • The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input.
  • After we enter an x value, the function outputs this sequence of values. The y values are those.
  • A function can be compared to a piece of equipment on an assembly line.
  • A few screws and nuts are located on one end of the assembly line, while a car is located on the other. The function is the device in the center. The domain is the screws and bolts that we insert into the machine. The car at the other can be thought of as the range.

Given function is : y = -16t^2 + 50t + 4

It hits the ground when y=0

0 = -16t^2 + 50t + 4

8t^2 -25t -2 = 0

t = 25/16 + (1/16)sqrt(625+64) = (25+26.25)/16 = 51.25/16 = 3.2 seconds

domain is t=0 to t=3.2  [3.2]

take the derivative and set it equal to zero to find maximum height

-32t +50 = 0

t = 50/32 = 25/16 = 1.5625 seconds

-16(25/16) + 50(25/16) + 4 = 34(25/16) + 64/16 = (17(25)+32)/8 = 57.125 = maximum height

range is y = 0 to 57.125 feet.   the discus goes from 4 feet to 57 1/8 feet and back down to 0 feet.

Know more about Domain and Range with the help of the given link:

brainly.com/question/20349151

#SPJ4

8 0
2 years ago
A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate
Lyrx [107]

Answer:

Therefore the rate change of height is  \frac{1}{\pi} m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

\frac{dV}{dt}=4 \ m^3/s

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is V=\pi r^2 h

                                                 =( \pi \times 2^2\times h)\ m^3

\therefore V= 4\pi h

Differentiating with respect to t.

\frac{dV}{dt}=4\pi \frac{dh}{dt}

Putting the value \frac{dV}{dt}

\Rightarrow 4\pi \frac{dh}{dt}=4

\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}

\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}

The rate change of height does not depend on the height.

Therefore the rate change of height is  \frac{1}{\pi} m/s.

3 0
3 years ago
Which are partial products for 68 × 43?
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The correct answer is D? Its the only one that makes sense.
6 0
3 years ago
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