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3 years ago

Can someone help me with these two

Mathematics

1 answer:

LenaWriter [7]3 years ago

4 0

Answer:

The first equation answer is 10

And the second one 6

Step-by-step explanation:

The first equation

2/5 x +3= 2/3x +1/3

2x + 15/5 = 6x+3/9 the cress cross

9(2x + 15) = 5(6x + 3)

18x + 135 = 30x +15

135-15 = 30x - 18x

120 = 12x

120/12 =12x/12

10 = x

X =10

The second one

-2.6b +4 =0.9b - 17

-2.6b - 0.9b = - 17 - 4

-2.6b + (-0.9b) = - 17 + (-4)

-3.5b = - 21

-3.5b/-3.5 = - 21 /-3.5

B= 6

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5. Sarah made 17 out of 25 free throws during practice. What percentage of free throws did she NOT make? A. 68% B. 58% C. 32% D.

Elanso [62]

Answer:

C. 32%

Step-by-step explanation:

The percent 17 is of 25.

17 of 25 can be written as:

17/25

To find percentage, we need to find an equivalent fraction with denominator 100. Multiply both numerator & denominator by 100

17/25 * 100/100

= (17 * 100/25) * 1/100 = 68/100

Therefore, the answer is 68%

If Sara made 68% of her free shows, that means she didn't make 32% of her free throws (100 - 68 = 32).

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2 years ago

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3 years ago

The point (Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, StartFraction StartRoot 2 EndRoot Over 2 EndFraction)

sveticcg [70]

The values of cosine Ф and cotangent Ф are $\frac{-\sqrt{2} }{2}$ and -1

Step-by-step explanation:

When a terminal side of an angle intersect the unit circle at

point (x , y), then:

The x-coordinate is equal to cosine the angle between the positive part of x-axis and the terminal side
The y-coordinate is equal to sine the angle between the positive part of x-axis and the terminal side
If x and y coordinates are positive, then the angle lies in the 1st quadrant
If x-coordinate is negative and y-coordinate is positive, then the angle lies in the 2nd quadrant
If x and y coordinates are negative, then the angle lies in the 3rd quadrant
If x-coordinate is positive and y-coordinate is negative, then the angle lies in the 4th quadrant

∵ The terminal ray of angle Ф intersects the unit circle at point $(\frac{-\sqrt{2} }{2},\frac{\sqrt{2} }{2})$

- According to the 1st and 2nd notes above

∴ cosФ = x-coordinate of the point

∴ sinФ = y-coordinate of the point

∵ The x-coordinate of the point is negative

∵ They-coordinate of the point is positive

- According the the 4th note above

∴ Angle Ф lies in the 2nd quadrant

∵ x-coordinate = $\frac{-\sqrt{2} }{2}$

∴ cosФ = $\frac{-\sqrt{2} }{2}$

∵ y-coordinate = $\frac{\sqrt{2} }{2}$

∴ sinФ = $\frac{\sqrt{2} }{2}$

- cotФ is the reciprocal of tanФ

∵ tanФ = sinФ ÷ cosФ

∴ cotФ = cosФ ÷ sinФ

∴ cotФ = $\frac{-\sqrt{2} }{2}$ ÷ $\frac{\sqrt{2} }{2}$

∴ cotФ = -1

The values of cosine Ф and cotangent Ф are $\frac{-\sqrt{2} }{2}$ and -1

Learn more:

You can learn more about the trigonometry function in brainly.com/question/4924817

#LearnwithBrainly

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3 years ago

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Viktor [21]

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3 years ago

How many solutions are there to the equation below 15x+11=8x

Svetradugi [14.3K]

Answer:

There is one solution

Step-by-step explanation:

15x+11=8x

Subtract 15x from each side

15x-15x +11 = 8x-15x

11 = -7x

Divide by -7

11/-7 = -7x/-7

-11/7 =x

There is one solution

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3 years ago

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