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Montano1993 [528]
3 years ago
12

5. A pole has to be erected at a point on the boundary of a circular park of diameter 13 metres in

Mathematics
1 answer:
lesya [120]3 years ago
4 0

Answer:

Thus, it is possible to erect a pole at a point p on the boundary of the park at distances 5m and 12m respectively from gates B and A.

Step-by-step explanation:

Let P be the required location of pole .

A and B are the two gates.

Let the distance of pole at p from gate be 'x' meters

i.e. PB = x m

•°• AP = (x + 7)m and AB = 13 m

•°• AP² + BP² = AB² => (x +7)² + x =13²

Rejecting x =-12, we get x = 5

•°• PB = 5m

and

AP = 12m

(I hope this helped :)

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castortr0y [4]

Answer:

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<em>Rounded to the nearest whole number` 2613cm^3.</em>

<em>The volume of cylinder is S*height, where S is the area of circle,</em>

<em>S=Pr^2 -> V=3.14*8*8*23=4624.42cm^3. Rounded to the nearest whole number` 4624cm^3.</em>

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8 0
3 years ago
What two positive real numbers whose product is 21 have the smallest possible​ sum?
GalinKa [24]

Answer:

x=\sqrt{21}

y=\sqrt{21}

Step-by-step explanation:

Let x  and y are the two positive real numbers

product of two numbers is 21

x y=21

y=\frac{21}{x}

The sum of the two numbers is f(x) =x+y

Replace y with 21/x

f(x) =x+\frac{21}{x}

we need to find smallest possible sum , so we take derivative using power rule

f'(x)= 1-\frac{21}{x^2}

when sum is minimum then the derivative is equal to 0

0= 1-\frac{21}{x^2}

0=\frac{x^2-21}{x^2}

multiply both sides by x^2

x^2-21=0

x^2=21

Take square root on both sides

x=\sqrt{21}

y=\frac{21}{x}

y=\frac{21}{\sqrt{21}}

y=\sqrt{21}

3 0
4 years ago
Choose all the expressions that have 3/4 as a product. 3/4 ×3/4, 9/10 × 5/6, 7/8 × 6/7, 1/4 × 1/2, 1/2 × 1/2.
aivan3 [116]

Answer:

9/10*5/6 and 7/8*6/7

Step-by-step explanation:

Multply each one and compare the quotient, rember to simplify

8 0
3 years ago
Read 2 more answers
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natulia [17]

Answer:

5

Step-by-step explanation:

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125 = 5 * 5 * 5

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If you look at the second graph and were to add the percentages, they add far higher than 100%. Why is that the case?
ser-zykov [4K]

Answer:

They could have asked more than 100 people or it just went over because of the percentages and they didn’t know

Step-by-step explanation:

5 0
3 years ago
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