The box plots display the final exam scores for two 7th grade math classes:

Write the polar coordinates (3, pi) in rectangular form. a. (0, 3) c. (-3, 0) b. (3, 0) d. (0, -3)

Misha Larkins [42]

In rectangular form, we have the coordinates $(3\cos\pi,3\sin\pi)=(3\cdot -1,3\cdot 0)=\boxed{(-3,0)}.$

3 0

3 years ago

There are some monkeys in the zoo. 60% are young monkeys and the remaining are baby and old monkeys. The ratio of baby monkeys t

USPshnik [31]

Answer:

There are 60 monkeys in the Zoo

Step-by-step explanation:

In this question, we are asked to calculate the number of monkeys in a Zoo given some information to use.

Let’s have the total number of monkeys be m.

60% are going monkeys. This means number of young monkeys is 0.6m.

The number of baby and old monkeys is obviously 0.4m.

Ratio of baby to old monkeys is 3:1. This means if we splitter 0.4m into 4, number of baby monkeys is 0.3m while number of old monkeys is 0.1m

Now, subtracting the number of baby monkeys from young monkeys give a total of 18 monkeys.

Let’s project this mathematically;

This means ;

0.6m - 0.3m = 18

0.3m = 18

m = 18/0.3

m = 60

There are 60 monkeys in the zoo

3 0

3 years ago

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QS¯¯¯¯¯¯¯ bisects ∠PQR . If m∠PQS = 5x and m∠RQS = 2x + 6, then what is m∠PQR ? m∠PQR is

soldi70 [24.7K]

Answer:

$PQR = 20$

Step-by-step explanation:

Given

Bisector: QS

$PQS = 5x$

$RQS = 2x + 6$

Required

Determine PQR

Since PQR is bisected to PQS and RQS, we have that

$PQS = RQS$

Substitute expressions for PQS and RQS

$5x = 2x + 6$

Collect Like Terms

$5x - 2x = 6$

$3x = 6$

Divide both sides by 3

$x = 2$

Solving for PQR;

$PQR = PQS + RQS$

$PQR = 5x + 2x + 6$

$PQR = 7x + 6$

Substitute 2 for x

$PQR = 7 * 2 + 6$

$PQR = 14 + 6$

$PQR = 20$

4 0

4 years ago

Please Help, I need it for my homework

Naily [24]

Answer:

A)

p1 (0,0) p2 (1,2) given from the graph

slope = (y2-y1)/ (x2-x1 )

slope (m) = 2

y = mx+ b

b =0

y = 2x

b)

x = 0

y = 5

(0,5)

C)

gradient = slope

y = 3x + b

point given (0,12)

y = 3x + 12

5 0

2 years ago

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Rewrite the quadratic function below in Standard Form. y = (x - 4) (x + 3)

Damm [24]

the standard form of a quadratic formula is

y = ax^2 + bx + c

in this case you will solve using foil method

(× - 4)(x + 3)

(x × x) +( x × 3 )(- 4 × x) ( -4)× 3))

x^2 + 3x - 4x -12

x^2 - x - 12

therefore

y = x^2- x - 12

5 0

3 years ago