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lianna [129]
3 years ago
6

Help with math. Please

Mathematics
1 answer:
Brrunno [24]3 years ago
6 0

Answer:

I DONT KNOW  THE ANSWER

Step-by-step explanation:

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The vertices of triangle ABC are A(-5, 1), B(-2.5, 7). and C(0, 1). Find the new coordinates of the vertices after the given tra
Crank

Answer:

A).

Step-by-step explanation:

Add 3 to the x values and subtract 1 from the y's.

For example  A ( -5, 1 ) ---->  (-5+3, 1 -1 ) ---> (-2, 0).

5 0
3 years ago
Plz answer this question fast
Nikolay [14]

Answer:

maybe A

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
HELP!! ASAP PLEASE!! WILL GIVE BRAINLIEST!!
patriot [66]

Answer:

6^-4 ÷ 3^-4

6^-4/3^-4

Since their powers are negative

Flip them both so the negative index is lost.

It now becomes

3^4/6^4

81/1296

=1/16

6 0
3 years ago
Can anybody help? Having a little trouble with this during quarantine...
kolbaska11 [484]
First you would have to find the base which would be 9^2 + 9^2= C^2 because of the pythagorean theorem. So the base would equal 12.7. To find the area of a triangle it’s A= h•b / 2. So your answer would be 95.25
6 0
3 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 449 gram setting. It is
stealth61 [152]

Answer:

We accetp  H₀

Step-by-step explanation:

Information:

Normal distribution  

Population mean      =   μ₀  = 449

Population standard deviation  σ   unknown

Sample size   n  =  23        n < 30    we use t-student test

so   n  =  23    degree of fredom   df = n  - 1  df  = 23- 1   df = 22

Sample mean    μ =  448

Sample standard deviation   s  =  20

Significance level  α  =  0,05  

1.-Hypothesis Test

Null hypothesis                               H₀     μ₀  =  449

Alternative hypothesis                    Hₐ     μ₀  ≠  449

Problem statement ask for determine decision rule for rejecting the null hypothesis. For rejecting the null hypothesis we have to  get an statistic parameter wich implies  that μ is bigger or smaller than μ₀

2.-Significance level   α  =  0,05  ;  as we have a two tail test

α/2    =  0,025

Then from t - student table for  df =  22   and 0,025 (two tail-test)

t(c)  =  ±  2.074

3.- Compute  t(s)

t(s)   =  (  μ  -  μ₀ )  /  s /√n

plugging in values

t(s)   =  (448  -  449) /  20 /√23    ⇒   t(s)   =  -  1*√23 /20

t(s)   =  - 0.2398

4.-Compare t(c)   and  t(s)

t(s)  <  t(c)         - 0.2398  <  - 2.074

Therefore  t(s)  in inside acceptance region.  We accept  H₀

7 0
4 years ago
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