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Vlad [161]
3 years ago
14

If​ Tucson's average rainfall is

Mathematics
1 answer:
S_A_V [24]3 years ago
4 0
You think I know right? yeah so no way boy I'm so sorry not my intencion
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Which of the following equations have no solutions?
Neporo4naja [7]

Option 3 is not possible

-60.2 + 32 = -60.2 + 60

And these are not equal

Rest all options have x and are solvable

Must click thanks and mark brainliest

5 0
3 years ago
Read 2 more answers
If the area of the blue square is 144 units2 and the area of the pink square is 1225 units2, then the length of the hypotenuse i
navik [9.2K]

Answer: 37 units

Step-by-step explanation:

Blue=144units^2 This also works as the height of the triangle.

Pink=1225units^2 This also works as the base of the triangle.

Let's call pink ''a'', and blue ''b''. The side we're looking for ''c'' is the hypothenuse.

To find the values of a and b, use the area formula of a square and solve for a side. In this case, since we're going to need the squared values, this step can be omitted.

Formula: A=s^2

s=\sqrt[]{A}

Let's work with Blue.

s=\sqrt[]{144units^2} \\s=12units

Now Pink.

s=\sqrt[]{1225units^2}\\s=35units

So we have a triangle with a base of 35 units and a height of 12 units.

Now let's use the pythagoream's theorem to solve.

c^2=a^2+b^2\\c=\sqrt[]{a^2+b^2} \\c=\sqrt[]{(12units)^2+(35units)^2}\\c=\sqrt[]{144units^2+1225units^2}\\ c=\sqrt[]{1369units^2}\\ c=37units

7 0
3 years ago
Jared is constructing a rectangular door for a shed. If the door, shown below, has a width of 42 in. and a diagonal support of 9
Goshia [24]

Answer:

B

Step-by-step explanation:

A rectangular door for a shed has a width of 42 in and a diagonal support of 94 in. The triangle formed by the rectangle's width (first leg), rectangle's length (second leg) and rectangle's diagonal (hypotenuse) is right triangle. By the Pythagorean theorem,

\text{leg}_1^2+\text{leg}_1^2=\text{hypotenuse}^2.

Thus,

42^2+x^2=94^2,\\ \\x^2=94^2-42^2=7072,\\ \\x=\sqrt{7072}=4\sqrt{442}\approx 84\ in

7 0
3 years ago
What is the equation, in standard form, of a circle with center (−5, 8) and radius 5?
skad [1K]

Answer:

( x + 5 )² + ( y - 8 )² = 25

Step-by-step explanation:

Standard form for the equation of a circle - ( x - h )² + ( y - k )² = r²

Where r = radius and Center is located at ( h , k )

We are given that the center is at ( -5 , 8 )

Thus, h = -5 and k = 8

We are also given that the radius = 5

Thus, r = 5

Now we just plug all of the given values into the standard form equation

( x - (-5))² + ( y - 8 )² = 5²

*simplify*

in - ( - 5 ) the two negative sign cancel out and it turns into + 5

5² = 25

Thus, the equation is ( x + 5 )² + ( y - 8 )² = 25

3 0
3 years ago
Zhen borrows $1,200. She borrows the money for 2 years and owes $180 in simple
Rashid [163]

Answer: 7.5

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 7.5%/100 = 0.075 per year,

then, solving our equation

I = 1200 × 0.075 × 2 = 180

I = $ 180.00

4 0
3 years ago
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