Find the dicontinuities of the function.
1 answer:
Answer:
Step-by-step explanation:
I'm assuming you meant to type in
because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to
and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.
The removable discontinuity is at -3. There is no y value at x = -3 (remember there's only a hole here), because -3 causes the denominator to go to 0 and we all know that having a 0 in the denominator of a fraction is a big no-no!!!
You might be interested in
The length of AB is (x + 4) cm and the values of a and be are a = 10, b = 4
A rectangle is a quadrilateral in which opposite sides are equal and parallel to each other. The area of a rectangle is:
Area = length * width
From the image:
Length of AB = x + 4
Length of BC = x + 6
The area of rectangle ABCD = Length of AB * Length of BC
28 = (x + 4)(x + 6)
x² + 10x + 24 = 28
x² + 10x = 4
Comparing with x² + ax = b gives:
a = 10, b = 4
Therefore the length of AB is (x + 4) cm and the values of a and be are a = 10, b = 4
Find out more at: brainly.com/question/15019502
