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dedylja [7]
2 years ago
13

Analyze the data represented in the table and select the appropriate model

Mathematics
1 answer:
Inessa05 [86]2 years ago
3 0

Answer: Option B, a linear relation.

Step-by-step explanation:

Let's analyze the points in the data:

the first 3 pairs are: (0,14.70) (10,19.03) and (20, 23.36)

We can see the differences between consecutive points and see if the relation is linear:

(10,19.03) -  (0,14.70) = ( 10 - 0, 19.03 - 14.70) = (10, 4.33) now we need to see the quotient: 4.33/10 = 0.433

(20, 23.36) - (10,19.03)  = (20 - 10, 23.36 - 19.03) = (10, 4.33), and the quotient is the same as before.

This means that the relation is a linear relation, where the slope os 0.433 and the x-intercept is 14.70, so the equation can be written as:

y(x) = 0.433*x + 14.70

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Answer this question.<br><br> You get a thank you and 5 stars if it's the correct answer.
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Answer:

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Step-by-step explanation:

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4 0
2 years ago
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Prove that if one solution for a quadratic equation of theform x2 + bx + c = 0 is rational (where b and c are rational),then the
Elenna [48]

Answer:

The other solution of the given equation x² + bx + c = 0   is also rational number.

Step-by-step explanation:

Here, given: ax² + bx + c = 0 is a quadratic equation

Also, one solution  (r)  of equation is RATIONAL.

To show: The other solution (s)  is also RATIONAL

Now, here: as x² + bx + c = 0

Since r and s are the two given solutions, the given equation can be factorized as:

x² + bx + c =  (x -r) (x - s)

Simplifying LHS, we get:

(x -r) (x - s) = x x - r (x) - s (x) +  (r)(s)

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or, x² + bx + c = x² + x(-r - s) +  rs

Comparing the related terms, we get:

b =  (-r - s)    

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or, s  = -r - b

Now, given : r = Rational  and the negative of a rational is also rational.

⇒  -r is also rational

Also, difference of two rational number is also rational.

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7 0
3 years ago
4535 divided by 83 = R =
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Answer:

54 R 53

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Step-by-step explanation:

4535 divided by 83 equals

54 with a remainder of 53

8 0
3 years ago
Please help worth lot of points
Nat2105 [25]
It could be y=1 possibly
5 0
3 years ago
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(csc x - 1) (csc x + 1)
victus00 [196]
<h2>Explanation:</h2>

Here we have the following expression:

(csc x - 1) (csc x + 1)

So we need to extend this. Remember that the difference of squares tells us:

(a-b)(a+b)=a^2-b^2

So here:

a=cscx \\ \\ b=1

Thus:

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4 0
3 years ago
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