Answer:
Salim can simplify that and the answer will be 
Step-by-step explanation:
This is because of the law of multiplying powers, which states that you can add the exponents if the base is the same. So, you just add m and n and put that as the exponent and you will have the answer.
Answer:
<em>1</em><em>2</em>
Step-by-step explanation:
<em>here's</em><em> your</em><em> solution</em>
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The sum of three primes is 18 so they must all be smaller than 18 as well.
Primes less than 18=2,3,5,7,11,13,17
2,3, and 13
2,5, and 11
There are two solutions...
Answer: The number is 26.
Step-by-step explanation:
We know that:
The nth term of a sequence is 3n²-1
The nth term of a different sequence is 30–n²
We want to find a number that belongs to both sequences (it is not necessarily for the same value of n) then we can use n in one term (first one), and m in the other (second one), such that n and m must be integer numbers.
we get:
3n²- 1 = 30–m²
Notice that as n increases, the terms of the first sequence also increase.
And as n increases, the terms of the second sequence decrease.
One way to solve this, is to give different values to m (m = 1, m = 2, etc) and see if we can find an integer value for n.
if m = 1, then:
3n²- 1 = 30–1²
3n²- 1 = 29
3n² = 30
n² = 30/3 = 10
n² = 10
There is no integer n such that n² = 10
now let's try with m = 2, then:
3n²- 1 = 30–2² = 30 - 4
3n²- 1 = 26
3n² = 26 + 1 = 27
n² = 27/3 = 9
n² = 9
n = √9 = 3
So here we have m = 2, and n = 3, both integers as we wanted, so we just found the term that belongs to both sequences.
the number is:
3*(3)² - 1 = 26
30 - 2² = 26
The number that belongs to both sequences is 26.
