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DiKsa [7]
3 years ago
5

A weather balloon on the ground has a volume of 200 L at 25.0 °C when filled with helium to a pressure of 100 kPa. What is the v

olume of the balloon (in L) at 9000 m, where the temperature is –50.0 °C and the pressure is 19.5 kPa?
Chemistry
1 answer:
Gennadij [26K]3 years ago
3 0
According to Gas law equations, we know, 
P₁V₁/T₁ = P₂V₂/T₂

Here, P₁ = 100 kPa
P₂ = 19.5 kPa
T₁ = 25+273 = 298k
T₂ = -50+273 = 223k
V₁ = 200 L
V₂ = ?

Substitute their values, 
100*200 / 298 = 19.5*V₂/223
20000*223 / 298*19.5 = V₂
V₂ = 4460000 / 5811
V₂ = 767.50 L

In short, Your Answer would be: 767.50 Liter

Hope this helps!
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What did you include in your hypothesis? Check all that apply.
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What is the chemical composition of the mobile phase in this experiment?
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3 years ago
Dinitrogen tetraoxide, N2O4, decomposes to nitrogen dioxide, NO2, in a first-order process. If k = 1.5 x 103 s-1 at 5 ºC and k =
Arada [10]

Answer:

The activation energy for the decomposition = 33813.28 J/mol

Explanation:

Using the expression,

\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )

Wherem  

k_1\ is\ the\ rate\ constant\ at\ T_1

k_2\ is\ the\ rate\ constant\ at\ T_2

E_a is the activation energy

R is Gas constant having value = 8.314 J / K mol  

Thus, given that, E_a = ?

k_2=4.0\times 10^3s^{-1}

k_1=1.5\times 10^3s^{-1}  

T_1=5\ ^0C  

T_2=25\ ^0C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (5 + 273.15) K = 278.15 K  

T = (25 + 273.15) K = 298.15 K  

T_1=278.15\ K

T_2=298.15\ K

So,

\ln \frac{1.5\times 10^3}{4.0\times 10^3}\:=-\frac{E_{a}}{8.314}\times \left(\frac{1}{278.15}-\frac{1}{298.15}\right)

E_a=-\ln \frac{1.5\times \:10^3}{4.0\times \:10^3}\:\times \frac{8.314}{\left(\frac{1}{278.15}-\frac{1}{298.15}\right)}

E_a=-\frac{8.314\ln \left(\frac{1.5\times \:10^3}{4\times \:10^3}\right)}{\frac{1}{278.15}-\frac{1}{298.15}}

E_a=-\frac{689483.53266 \ln \left(\frac{1.5}{4}\right)}{20}

E_a=33813.28\ J/mol

<u>The activation energy for the decomposition = 33813.28 J/mol</u>

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3 years ago
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