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vampirchik [111]
3 years ago
13

What does water moves under earth's surface to fill in open spaces in rocks or soil?

Chemistry
1 answer:
Trava [24]3 years ago
4 0
Water moves under the earth's surface to fill in open spaces in rocks or soil. This type of water is called groundwater.
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After our solar system began to form, dust and gas combined into small bodies that formed the planets. What are these small bodi
saul85 [17]

Answer:

Planetesimal

Explanation:

According to Nebular Theory, the Solar system was formed from the Solar Nebula about 4.6 billion years ago. Nebula is a molecular cloud composed of dust and gases. Majority of the mass accreted to form a core which gradually formed the Sun. The remaining mass of the disk surrounding the core accreted into small bodies known as Planetesimal which formed the planets.

7 0
3 years ago
Read 2 more answers
During science lab, Carl notices that when he adds water to his solid sample of anhydrous copper
Bond [772]

Answer:

The dissociation of copper sulfate into ions is an exothermic chemical reaction that releases heat into the surroundings.

Explanation:

Some of the potential energy stored in the solid sample of anhydrous copper sulfate is released as heat as the sample dissolves and dissociates into ions in the water. This is due to the large lattice energy of the crystalline copper sulfate.

hope this helps

4 0
3 years ago
A sample of lead has a density of 11.3 g/cm3 and a mass of 123 grams, what is the volume of the sample?
SVEN [57.7K]

Answer:

The answer is

<h2>11.18 cm³</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 123 g

density = 11.3 g/cm³

The volume is

volume =  \frac{123}{11.3}   \\  = 11.18181818...

We have the final answer as

<h3>11.18 cm³</h3>

Hope this helps you

3 0
3 years ago
They all have the same choices but one of them its not gonna be used.​
Dima020 [189]

Answer:

limiting reactant

Explanation:

it is consumed totally

3 0
2 years ago
Is 13.0 mv at 25 °c. calculate the concentration of the zn2 (aq) ion at the cathode?
Andrews [41]
Answer: 
 Zn =⇒ Zn+2(0.10) + 2e- (anode)
 Zn+2(?M) + 2e- === Zn(s) (cathode)
 
 Zn + Zn+2(?M) ===⇒ Zn+2(0.10) + Zn 
 E = E^o -0.0592 log Q; in this case E^o is zero. 
 E = - 0.0592 /n logQ where n is the number of electrons transferred, in this
case n = 2 
 23 mV x 1 volt/1000mv = 0.023 Volts 
 0.023 = -0.0592 / 2 log(0.10) / [Zn+2]
 0.023 = -0.0296 { log 0.10 – log [Zn+2] }
 0.023 = -0.0296{ -1 - log[Zn+2] }
 0.023 = +0.0296 + 0.0296log[Zn+2]
 -0.0066 = 0.0296log[Zn+2]
 -0.22= log[Zn+2]
 [Zn+2] = 10^-0.22 = 0.603 Molar

6 0
3 years ago
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