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3 years ago

Sketch a graph of f (x) = −1

Mathematics

1 answer:

Eduardwww [97]3 years ago

8 0

Answer:

Step-by-step explanation:

f(x) = -1 is actually the same as y = -1. Find y = -1 on the y axis and then draw a horizontal line through this point. The resulting graph is that called for here.

You might be interested in

What is measure of side A?

Ira Lisetskai [31]

Answer:

The correct answer option is c. a = 11.94.

Step-by-step explanation:

We are given a right angles triangle with an angle ABC equal to 58 degrees and side length AC known to be equal to 19.1.

We are supposed to find the length of side a.

Side AC, opposite to angle ABC, will be the perpendicular and BC will be the base so we will use the formula of tan to find b.

$tan 58 = \frac{19.1}{a}$

$a = \frac{19.1}{tan 58}$

$a=11.94$

8 0

3 years ago

How would you graph this?? need help fast

statuscvo [17]

Answer:

There is no graph .... Please next time add one :)

Step-by-step explanation:

8 0

3 years ago

Write 18 1/4 as a decimal

nevsk [136]

Answer:

18.25

Step-by-step explanation:

1/4 = 0.25

7 0

2 years ago

Read 2 more answers

Find the value of x. 1) 46° x

ehidna [41]

There's no question there. You didn't attach the pic

6 0

3 years ago

The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th

inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4 -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

$y(y-2)=100$

$y^2-2y=100$

subtracting 100 from both sides

$y^2-2y-100=0$

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

$ax^2+bx+c=0$

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

$y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

Solving first

$y=\frac{2+\sqrt{4+400}{2}$

$y=\frac{2+\sqrt{404}{2}$

$y=\frac{2+20.099}{2}$

$y=\frac{22.099}{2}$

$y=11.049$

Solving second one

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{2-\sqrt{4+400}{2}$

$y=\frac{2-\sqrt{404}{2}$

$y=\frac{2-20.099}{2}$

$y=\frac{-18.99}{2}$

$y=-9.045$

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0

3 years ago