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Reptile [31]
3 years ago
9

For a class experiment, Danny's class weighed a log before and after subjecting it to termites. Before subjecting it to termites

, the log weighed 5 pounds. After the termites, the log weighed 1/4 of a pound. How much weight did the termites take from the log?
Mathematics
1 answer:
m_a_m_a [10]3 years ago
7 0

Answer:

4.75 pounds

Step-by-step explanation:

Before the termites: 5 pounds

After the termites: 1/4 of a pound

Amount that the termites took: x

5 - x = 1/4

Add x to both sides of the equation

5 = 1/4 + x

Subtract 1/4 from both sides of the equation

4 3/4 = x

4 3/4 = 4.75

The termites took 4.75 pounds from the log

Hope this helps :)

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\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

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\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

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We can simplify this by factoring:

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Step-by-step explanation:

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