Answer:

Step-by-step explanation:
Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m
Dimensions of a small locker are 0.5 m × 0.6 m ×
(as height of small locker is half the height of big locker )
To find: total volume of one big locker and one small locker
Solution:
Volume of cuboid = length × breadth × height
Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker
= 

You need to show us what the triangle is
1 3/9 but if reduce to lowest term than 1 1/3
Answer:
c = -6
d = 2
Step-by-step explanation:
After reflection about the x-axis:
A --> A'
(2,3) --> (2,-3)
(4,3) --> (4,-3)
(2,6) --> (2,-6)
After translation:
(2 + c, -6 + d) --> (-4, -4)
2+c = -4
c = -6
-6+d = -4
d = 2