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vovikov84 [41]
4 years ago
15

How to classify this equation and if it represents a function?

Mathematics
1 answer:
ehidna [41]4 years ago
7 0
Idk I'm just trying to get MY HOMEWORK DONE BEFORE BED!! I have an orchestra concert tomorrow so no time and it's due on Friday
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Triangles MOP and MNQ are similar. Find x.<br><br> 2<br><br> 3<br><br> 4<br><br> 5
Diano4ka-milaya [45]

Answer:

x = 3

Step-by-step explanation:

MQ : MN = 5:6

MP : MO = 5:6

MQ/MN = 5/6

Hence, MP/MO = 5/6

(5+x)/(6+(18/5)) = 5/6

5+x = (5/6)(48/5)

5+x = 8

x = 3

4 0
3 years ago
Suppose the only measuring cup you own is a one-third measuring cup. Using this measuring cup how many scoops will you need to h
Mariulka [41]

Answer:

11

Step-by-step explanation:

for each full cup of sugar, you need 3 one-third measuring cups.

we have 3 full cups so 3×3=9

and another 2 for the 2/3, 9+2=11

so a total of 11 scoops

5 0
2 years ago
Solve for X<br> Your answer must be simplified.<br><br> -7x &gt; 10
Bezzdna [24]

Answer:

There are many solution for this problem

The solutions are -2, -3, -4..... And even fractions like -11/7, -12/7, etc.

Hope this helps!

7 0
3 years ago
Read 2 more answers
The width of a rectangle is
Alisiya [41]

Answer:

let length be x

b = x - 3

perimeter = 2( l + b)

54 = 2(x+x-3)

27 = 2x - 3

30 = 2x

x = 15

l = 15

b = 15 - 3

b = 12

7 0
3 years ago
Incorrect, 12.1.53
Ganezh [65]

0.442

Step-by-step explanation:

Step 1 :

Given that 11% of the lights are defective.

So probability of a light randomly chosen is defective is .11

This implies probability of a light randomly chosen is not defective is 1 - .11 = .89

Step 2 :

In a pack of 5 light bulbs the probability that none of them are defective is (0.89)^ 5

Hence the probability that at least one of the light bulbs is defective is

1-(0.89)^ 5  = 1 - 0.558 = 0.442

5 0
3 years ago
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