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telo118 [61]
3 years ago
7

How do you solve a/7-5/7=6/7?

Mathematics
1 answer:
qaws [65]3 years ago
3 0
Here is you answer , happy today

You might be interested in
Express 112 as a product of prime numbers in index form?
alexgriva [62]
                                   112
                                    /  \
                                  2   56
                                       /  \
                                     2   28
                                          /  \
                                         2  14
                                              /  \
                                             2  7

So, the answer is 2 x 2 x 2 x 7 or 2^3 x 7
6 0
3 years ago
(1 point)
san4es73 [151]

Answer:

Step-by-step explanation:

2x - 9y = 23

5x - 3y = -12x - 9y = 23

5x - 3y = -1

7 0
3 years ago
Solve the equation<br> -18 + 24 = -2(x+6)
anzhelika [568]

Answer:

x = -9

Step-by-step explanation:

-18+24 = -2(x+6) Distribute and simplify

6 = -2x-12 Add 12 to both sides

18 = -2x Divide by -2 on both sides

-9 = x Here's your answer

Hope this helps! :D

3 0
1 year ago
Read 2 more answers
This is right or wrong, please anyone
BabaBlast [244]
Wrong,

You added when you were supposed to divide.

24/30 = 0.8


7 0
2 years ago
Read 2 more answers
Which of the following are identities? Check all that apply
Natasha2012 [34]

Answer:

A, C

Step-by-step explanation:

Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.

Examining

A) True

\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}

Double angle tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}

B) False,

No further development towards a Trig Identity

C) True

Double Angle Sine Formula sin2\alpha =2sin\alpha *cos\alpha

sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)

D) False No further development towards a Trig Identity

[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)

7 0
3 years ago
Read 2 more answers
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