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3 years ago

How do you solve a/7-5/7=6/7?

Mathematics

1 answer:

qaws [65]3 years ago

3 0

Here is you answer , happy today

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Express 112 as a product of prime numbers in index form?

alexgriva [62]

112
/ \
2 56
/ \
2 28
/ \
2 14
/ \
2 7

So, the answer is 2 x 2 x 2 x 7 or 2^3 x 7

6 0

3 years ago

(1 point)

san4es73 [151]

Answer:

Step-by-step explanation:

2x - 9y = 23

5x - 3y = -12x - 9y = 23

5x - 3y = -1

7 0

3 years ago

Solve the equation<br> -18 + 24 = -2(x+6)

anzhelika [568]

Answer:

x = -9

Step-by-step explanation:

-18+24 = -2(x+6) Distribute and simplify

6 = -2x-12 Add 12 to both sides

18 = -2x Divide by -2 on both sides

-9 = x Here's your answer

Hope this helps! :D

3 0

1 year ago

Read 2 more answers

This is right or wrong, please anyone

BabaBlast [244]

Wrong,

You added when you were supposed to divide.

24/30 = 0.8

7 0

2 years ago

Read 2 more answers

Which of the following are identities? Check all that apply

Natasha2012 [34]

Answer:

A, C

Step-by-step explanation:

Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.

Examining

A) True

$\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}$

Double angle $tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}$

B) False,

No further development towards a Trig Identity

C) True

Double Angle Sine Formula $sin2\alpha =2sin\alpha *cos\alpha$

$sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)$

D) False No further development towards a Trig Identity

$[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)$

7 0

3 years ago

Read 2 more answers