Answer: 05%
Step-by-step explanation:
60-57=3
3/60=0.05
0.05x100=5
Answer:
Option B is correct answer.
Step-by-step explanation:
We need to solve the expression sec2xcot2x.
We know sec x = 1/ cos x and cot x = 1/ tan x and tan x = sin x/cos x and 1/tanx = cosx /sinx
Since in question we 2x instead of x so, replacing x with 2x and Putting values:
So, Option B is correct answer.
Answer:
(A) When the sample size increases, both α and β may decrease.
Step-by-step explanation:
Which of the following is correct?
(A) This option is right.
When a sample's size increases, the values for alpha and beta may decrease; if and only if sample size is the denominator in the slope equation (in each case) and the numerator stays the same (that is, ceteris paribus; all other things being equal). The larger the denominator, the smaller the slope value for alpha and beta.
(B) This option is wrong
Type 2 error can only occur when you fail to reject a true H0
(C) This option is wrong
Type 1 error can only occur if or when you don't reject a false H0
(D) This option is wrong
The level of significance is the probability of a Type 1 error, not the probability of a Type 2 error.
Hello :
(-6a)-(-3a) =(-3a)-(0) = (0)-(3a) = (3a)-(6a) = -3a (arthmetic<span> sequence, the common - diff is : d= -3a the first term is : U1 = 6a
</span><span>a general rule for the n th term is : Un =U1+(n-1)d
Un = 6a +(n-1)(-3a) =
Un = 6a -3an+3a
</span>Un = -3an +9a