Answer:

Step-by-step explanation:
Given:
- p(x) = 2x2 - 1
- q(x) = 3(x - 1)
To find:
We know:
Substitute

3y - 1 = 28
+ 1 + 1
----------------
3y = 29
---- ----
3 3
y= 9.66
<span>complex roots (zeros) occur in conjugate pairs __ if 7+4i is a zero, then 7-4i is also a zero
for the coefficients to be rational; any irrational zeros (sqrt(7)) must have a conjugate, so -sqrt(7) is also a zero</span>