They are mixed, and the proportions are correct.
The distance between the campsite and the rest area is 9 miles.
The given parameters:
- <em>Initial speed of the campers, u = 4.5 mph</em>
- <em>Final speed of the campers, v = 4 mph</em>
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Let the time of motion from the campsite to rest area = t (hours)
Time for return trip = t hours + 15 mins
= (t + 0.25) hours
Let the distance between the campsite and rest area = d
d = 4.5t
d = 4(t + 0.25)
4.5t = 4(t + 0.25)
4.5t = 4t + 1
4.5t - 4t = 1
0.5t = 1
t = 2 hours
The distance between the campsite and the rest area is calculated as follows;
d = 4.5t
d = 4.5 x 2
d = 9 miles
Thus, the distance between the campsite and the rest area is 9 miles.
Learn more about distance and speed here: brainly.com/question/2854969
Answer:
The answer is "9"
Explanation:
In the given-question, the attachment file, which is "graph" is missing. so, in this question, firstly we add the file and then provide the solution:
please find the attachment of the image file.
Solution:
In the given graph by canceling, the out ends for getting the middle median that is equal to 2, that's why its value is equal to "9".
